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Umnica [9.8K]
3 years ago
10

At the bookstore, 40 copies of a popular paperback book fit perfectly on a 5-foot shelf. How many copies of this book would fit

perfectly on an 8-foot shelf? A. 72 books B. 60 books C. 68 books D. 64 books
Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

64 books

Step-by-step explanation:

The first step is to find the number of books that will fit in the shelve per foot

= 40/5

= 8

Therefore the number of books that will fit perfectly in 8-foot shelf can be calculated as follows

= 8×8

= 64

Hence 64 books would fit in 8-foot shelf

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I’m pretty sure it’s this 200,000
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3 years ago
Find an equation of the line described. Store the equation in slop-intercept form when possible.
Finger [1]

Answer:

Y = -5

Step-by-step explanation:

The line needs to be parallel to the y-axis, which means it forms a 90° angle with the y-axis. This means the line we are looking for is a straight horizontal line. The line must pass through the point (-7, -5), but we can disregard the x value since we figured out that the line is perfecly horizontal, so it has no x value. The answer we are left with is y = -5, which is a horizontal line across -5 on the y axis.

Hopefully you can understand my explanation :)

6 0
3 years ago
Sam's Club has a special that charges $2.49 per case of water. Vinny wants to pay that price, but needs to purchase a membership
castortr0y [4]

Answer: $50 + $2.49x = $67.43

Step-by-step explanation:

Let the case of water bought be represented by x.

We are informed that Sam's Club has a special that charges $2.49 per case of water and that Vinny wants to pay that price, but needs to purchase a membership first, which costs $50 and that Vinny eventually spent $67.43.

The equation that represents the number of cases of water that Vinny bought at Sam's club will be:

$50 + $2.49x = $67.43

8 0
3 years ago
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.
Oduvanchick [21]

Answer:

11402.66 m^{2}

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by \frac {0.5\pi d^{2}}{4}

Total area of semi circle will be 2\times\frac {0.5\pi d^{2}}{4}

Substituting 74 m for d and \pi as 3.14 we obtain

Total area semi-circle=2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}

Area of rectangle is given by the product of length and width

Rectangular area=96 m*74 m=7104 m^{2}

Total area of rectangular and semi-circles will be

4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}

Therefore, area of training field is 11402.66 m^{2}

6 0
4 years ago
Express it in slope-intercept form.
vekshin1

Answer:

y=(2/3)x+1

Step-by-step explanation:

Slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.

To find the slope, we need two points. From the graph, we can see that (0,1) and (3,3) are valid points.

(0,1) is coincidentally also the y-intercept, so b=1.

The slope is (3-1)/(3-0)=2/3

The equation of the line is thus:

y=(2/3)x+1

5 0
3 years ago
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