Find 1n( — 290.9).<br> Help<br> Pleaseeee my test is timed

Margo can purchase tile at a store for $0.79 per tile and rent a tile saw for $24. At another store she can borrow the tile saw

Monica [59]

$0.79 t + 24 =1.19t \\ \\ 1.19t - 0.79t =24 \\ \\ 0.4t =24 \\ \\ t =60 \\ \\ \\ \sf So, ~if~he~buys~60~tiles, ~then~the~price~will~be~the~same.$

4 0

3 years ago

Solve equality and inequalities 9/4(w-1/9)=7/2

alexdok [17]

The Answer To This Problem Is W=5/3 DownLoad Photo Math For These kinda questions, it will give you all the answers

7 0

3 years ago

In Chicago a taxi ride cost $3.25 plus $1.80 for each mile traveled. Debbie has budgeted $19 for a taxi ride (excluding tip) how

frutty [35]

Write an equation based on the problem
3.25 is fixed cost, and 1.80 is variable cost, so the equation will be
3.25 + 1.80x = 19.00
x represents the distance she can travel

Solve the equation
3.25 + 1.80x = 19.00
1.80x = 19.00 - 3.25
1.80x = 15.75
x = 15.75/1.80
x = 8.75

She can travel 8.75 miles for the taxi ride

8 0

3 years ago

A car ride is drawn on a coordinate plane so that the first card is located at the point by (5,10) what are the coordinates of t

Rudiy27

Answer:

There are two possible solutions:

Clockwise rotation

$P'(x,y) = (-10,5)$

Counterclockwise rotation

$P'(x,y) = (10, -5)$

Step-by-step explanation:

There are two possible answers: (i) Clockwise rotation, (ii) Counterclockwise rotation. Vectorially speaking, rotation of point of rotation of a point about another point of reference is defined by:

$P'(x,y) = O(x,y) + r_{OP}\cdot (\cos (\theta_{OP}\pm \theta'),\sin (\theta_{OP}\pm \theta'))$ (1)

Where:

$O(x,y)$ - Point of reference.

$r_{OP}$ - Length of the segment OP.

$\theta_{OP}$ - Direction of segment OP, measured in sexagesimal degrees.

$\theta '$ - Angle of rotation, measured in sexagesimal degrees.

Please notice that clockiwise rotation occurs when $\theta = \theta_{OP}-\theta'$ and counterclockwise rotation when $\theta = \theta_{OP}+\theta'$ . In addition, we define length and direction of the segment below:

$r_{OP} = \sqrt{(x_{P}-x_{O})^{2}+(y_{P}-y_{O})^{2}}$ (1)

$\theta_{OP} = \tan^{-1} \frac{y_{P}-y_{O}}{x_{P}-x_{O}}$

If we know that $x_{O} = y_{O} = 0$ , $x_{P} = 5$ , $y_{P} = 10$ and $\theta' = 270^{\circ}$ , then the coordinates of the first car after rotation is: