Angle two is 39° because of the law of congruent angles within two parallel lines
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer:
14x+6z
Step-by-step explanation:
distribute 2 into (4x-3z) and 3 into (2x+4z)
8x-6z+6x+12z
combine like terms
8x+6x=14x
12z-6z=6z
14x+6z
hope this helps
36(x)=900(100)
Cross products
36x divided by 36=90,000 divided by 36
Divide each side by 36
X=2500
Answer:
g=-19+9
g=-10
Step-by-step explanation: