Given two numbers x and y such that:
x + y = 12 ... (1)
<span>two numbers will maximize the product g</span>
from equation (1)
y = 12 - x
Using this value of y, we represent xy as
xy = f(x)= x(12 - x)
f(x) = 12x - x^2
Differentiating the above function:
f'(x) = 12 - 2x
Maximum value of f(x) occurs at point for which f'(x) = 0.
Equating f'(x) to 0 we get:
12 - 2x = 0
2x = 12
> x = 12/2 = 6
Substituting this value of x in equation (2):
y = 12 - 6 = 6
Therefore, value of xy is maximum when:
x = 6 and y = 6
The maximum value of xy = 6*6 = 36
The answer is x=4, y=-2 and the ordered pair would be (4,-2) good luck
Standard error (SE)
Or
Therefore, SE of the mean = (8)/(2) =4
Answer:
C
Step-by-step explanation:
-4+(-5)=-9
-4=-9+5
-4=-4......correct
