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Ira Lisetskai [31]
2 years ago
13

Arthur weighs 34 lb more than Lily. Their combined weight is 180 lbs less than four times Lily's weight. How much does Arthur we

igh?
Mathematics
1 answer:
mote1985 [20]2 years ago
5 0
X = Lilys weight
x + 34 = Arthurs weight
4x - 180 = combined weight

x + x + 34 = 4x = 180
2x + 34 = 4x - 180
-2x           -2x
_________________
        34 = 2x -180
     +180        + 180
_______________
       214 = 2x
        107  = x  which is Lily's weight
         141 = x + 34 which is Arthur's weight
The total weight is 248

which is the answer that you get when you do 4(107) = 180 or
428 -180 = 248

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A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of 2π/3
Aleksandr-060686 [28]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Radius of circle = 10 inches

Central angle is given by

\frac{2\pi }{3}

As we know the formula for " Length of an arc " :

Length of arc is given by

l=r\theta\\\\l=10\times \frac{2\pi}{3}\\\\l=10\times \frac{2}{3}\times \frac{22}{7}\\\\l=20.95\ inches

Hence, length of an arc is 20.95 inches.

Hence, Option 'C' is correct.

5 0
3 years ago
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Find the area of a circle with a radius of 48mm
Ainat [17]

Answer:

A≈7238.23

Step-by-step explanation:

A=πr2

Area =π(48)2

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Can you convert each standard-form equation to slope-intercept form and type the correct code? Please remember to type in ALL CA
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Answer: Don't know sorry

Step-by-step explanation:

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2 years ago
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

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8 0
3 years ago
What is the value of x if 5x+2 = 59?
lana66690 [7]

Answer:

x = 57/5 = 11.400

Step-by-step explanation:

Step  1  :

Solving a Single Variable Equation :

1.1      Solve  :    5x-57 = 0

Add  57  to both sides of the equation :

                     5x = 57

Divide both sides of the equation by 5:

                    x = 57/5 = 11.400

One solution was found :

                  x = 57/5 = 11.400

Processing ends successfully

plz mark me as brainliest :)

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3 years ago
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