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Aleksandr [31]
3 years ago
7

Which expressions are equivalent to the one below? Check all that apply. 3^4 • 3^x

Mathematics
2 answers:
Wittaler [7]3 years ago
7 0

Answer: 3^4+x, 81•3^x

Step-by-step explanation:

skksbdndjfjdndjdndndnddkjdjdndndmdmdmdmdndndndnndn

Brums [2.3K]3 years ago
4 0

Answer:

B and D

Step-by-step explanation:

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What is the square root of 504 simplified ?
Reil [10]

Answer:

6\sqrt{14}

Step-by-step Explanation:

     To simplify \sqrt{504}, we will look for numbers that 504 can be divided by until there are no perfect square roots under the radical.

[] To do this, we can think of perfect square roots such as 4, 9, 16, etc

We can divide 504 by 36 for an answer of 14, so \sqrt{504} can be written as \sqrt{36*14} which can be written as 6\sqrt{14} because the square root of 36 is 6.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0
2 years ago
Math 2 Of high school
Daniel [21]

Answer:

  • B. BC = 18 so ∆ABC ~ ∆DEF by SAS

Step-by-step explanation:

\bf \cfrac{AB}{DE}  =  \cfrac{BC}{EF}

  • \bf \cfrac{15}{10}  =  \cfrac{BC}{12}
  • \bf  \cfrac{3}{2}  =  \cfrac{BC}{12}
  • \bf BC =  \cfrac{3}{2}  \times 12
  • \bf 3 \times 6
  • \bf BC = 18
  • \bf \angle B = \angle \: E

So, ∆ABC ~ ∆DEF by SAS.

<h3><u>------------------------------------</u></h3>
7 0
2 years ago
1/3(6x-12)=8(1/2x+1)-2
dlinn [17]
X = -5 is the answer I believe
8 0
3 years ago
How to solve 2/10b=99
soldier1979 [14.2K]
Multiply both sides by 10.
2b=990
divide both sides by 2
b= 495
6 0
3 years ago
(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

4 0
3 years ago
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