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4 years ago

True or False? Shapes that have no right angles also have no perpendicular segments.

Mathematics

2 answers:

frosja888 [35]4 years ago

4 0

I think this is True. Because Perpendiculer Lines Rely On Right Angles. :)

Keith_Richards [23]4 years ago

4 0

The answer is true I hope that's help.

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2.789 in word form and in expanded form

mylen [45]

Word form:
Two and seven hundred eighty-nine thousandths

Expanded form:

2

+ 0.7

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5 0

3 years ago

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Last week, Riley worked 7.5 hours per day for 3 days and earned a total of $306.45.

maria [59]

Answer:

13,62$

Step-by-step explanation:

The total hours Riley worked last week: 7.5*3= 22.5 (hours)

Riley's hourly rate of pay: 306.45/ 22.5= 13.62$

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3 years ago

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Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago

Between 10 a.M. And 11 a.M., 48 people came into Brad's store. 40 of them made a purchase. What is the experimental probability

irina [24]

Answer: The required probability is $\dfrac{5}{6}$

Step-by-step explanation:

Since we have given that

Number of people came into Brad's store = 48

Number of them made a purchase = 40

So, the experimental probability that the next person to come into the store will make a purchase would be

$\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}\\\\=\dfrac{40}{48}\\\\=\dfrac{5}{6}$

Hence, the required probability is $\dfrac{5}{6}$

4 0

4 years ago

Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir

DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation $\mathbf{ \dfrac{dy}{dx} =f (x,y) }$ with 2 variables x & y, including its function f(x,y) specified on a xy-plane.