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3 years ago

True or False? Shapes that have no right angles also have no perpendicular segments.

Mathematics

2 answers:

frosja888 [35]3 years ago

4 0

I think this is True. Because Perpendiculer Lines Rely On Right Angles. :)

Keith_Richards [23]3 years ago

4 0

The answer is true I hope that's help.

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Find the sum of the measures of the interior angles of a convex 30-gon.

Kisachek [45]

The sum of the interior angles of a polygon with N sides is (N-2) x 180 degrees.

For a 30-gon, the sum of interior angles is (28) x (180) = 5,040 degrees.

It makes no difference whether or not the polygon is convex at every vertex.

7 0

3 years ago

Read 2 more answers

2+2-8-*456*7524+7+46426+*545/65/6213-543+3112+91456+210256488765454 Answer within 10 min

zvonat [6]

Answer:

My calculator said error and i tried looking it up it said error too. I'm sorry I tried, you'll have to do it by hand

Step-by-step explanation:

5 0

3 years ago

Karla's jewelry box is shaped like a rectangular prism. The bottom surface of the box has an area of 65 square inches. The heigh

koban [17]

Answer:

780 cubic inches

Step-by-step explanation:

Step one:

Given data

The bottom surface of the box has an area of 65 square inches.

Already given an area and a height of 12 in

we proceed to find the volume by multiplying Area and height

Required

The volume of the box

Volume= Area* height

Step two:

Volume= 65*12

Volume = 780 cubic inches

6 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

Teacher has 1p she buys 10 boxes worth 10p how much does she have to pay

Levart [38]

100p? if you would like to explain what the variable p is i could help out

6 0

3 years ago