D. 14
LL = 1/2 * Hsqrt3
7sqrt3 = 1/2 * ysqrt3
24.25 = ysqrt3
24.25/sqrt3 = y
y = 14
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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Answer:
Step-by-step explanation:
x + 2y = 8 -----------(I)
x - 2y = -4 -----------(II)
Add equation (I) & (II) and thus y will be eliminated and we can get the value of 'x'
(I) x + 2y = 8
(II) <u>x - 2y = -4</u><u> </u>{Now add}
2x = 4
x = 4/2
x = 2
Substitute x = 2 in equation (I)
2 + 2y = 8
2y = 8 - 2
2y = 6
y = 6/2
y = 3
Keeping in mind that x = rcos(θ) and y = rsin(θ).
we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.
