Hey mate !!
Here's your answer !!
2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0
2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0
Hence
2w - 3 = 0
2w = 3
w = 3/2
w - 4 = 0
w = 4
Hence value of w are 4 and 3/2
Hope this helps!!
Cheers!!
Answer:
y = -6
x = 1
Step-by-step explanation:
-x + 2y = -13
-x - 2y = 11
Sum the equations:
-x -x = -2x
+2y - 2y = 0
-13 + 11 = -2
then
-2x = -2
x = -2/-2
x = 1
from the first eq.
-x + 2y = -13
-1 + 2y = -13
2y = -13 + 1
2y = -12
y = -12/2
y = -6
check:
from the second eq.
-x -2y = 11
-1 -(2*-6) = 11
-1 -(-12) = 11
-1 + 12 = 11
X= 6
Y= 0
Z= -2
CHECK
3x + y -2z =22
3(6) + 0 -2(-2) =22
18 + 0 +4= 22
22=22
x+5y+z =4
6 +5(0)+ -2 =4
6 + 0 +-2 = 4
4=4
x+3z=0
6 + 3(-2) =0
6 -6 = 0
0=0
Answer:
70%
Step-by-step explanation:
because all percent are out of 100
so we would time both top and bottom number with 10
which would be 70/100
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is