A rectangular prism has 4 layers with 6 cubes in each layer. What is the volume of the rectangular prism in cubic cm?

Which two numbers on the number line have an absolute value of 1.75? Select the location of both numbers on the number line

hram777 [196]

Solution

To find Which two numbers on the number line have sn

absolute value of 1.75 .

Absolute value means " how far a number is from

zero " .

"1.75" is 1.75 away from zero .

and " -1.75" is also 1.75 away from zero .

i.e

| 0 - 1.75 | = 1.75

| 1.75 - 0 | = 1.75

So , the absolute value of "1.75" is 1.75

similarly , absolute value of "1.75" is 1.75 .

Hence , the two numbers are -1.75 and 1.75 .

8 0

3 years ago

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Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?

V125BC [204]

Answer:

So then our significance level is $\alpha=0.05$ and we need to remember these two conditions:

1) If the p value $p_v$ we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value $p_v \geq \alpha$ we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is $\alpha=0.05$ and we need to remember these two conditions:

1) If the p value $p_v$ we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value $p_v \geq \alpha$ we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

7 0

3 years ago

6+5(a-1)=36 please answer me

azamat

i think the answer is 35

6 0

3 years ago

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Select the correct order for the following numbers

Andru [333]

Answer:

cdab

Step-by-step explanation:

3 0

3 years ago

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. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago