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Ksenya-84 [330]
3 years ago
12

How many significant figures in 0.003010

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0
4 significant figures.
we can start counting the numbers after all the zeros in front. the zeros in front doesn't count in. but the zeros after the first number that is 1 or larger counts.
therefore we only need to look at 3010
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Sophie [7]
<h3>Answer: A) 24</h3>

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Work Shown:

(angle FXM) + (angle MXA) = angle FXA

(angle FXM) + 72 = 96

(angle FXM) + 72 - 72 = 96 - 72

angle FXM = 24

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What is the missing number?<br>45/9 = 12 - ?​
shutvik [7]

Answer:

7

Step-by-step explanation:

45/9 = 5

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Answer: Each multiple choice question is worth 5 points.


Step-by-step explanation: You can find this answer by using the equation "14m + 24 = 16m + 14" and then solving for "m". To find what "m" is, you must first subtract 14m from both sides, leaving "24 = 2m + 14". Next, you subtract 14 from both sides, leaving "10 = 2m". Finally, you divide both sides by 2, which will give you "m = 5". Thus meaning each multiple choice question is worth 5 points.

To check this, simply fill in for "m" and solve each side. 14 * 5 + 24 = 94 and 16 * 5 + 14 = 94. 94 = 94, so "m = 5" is correct.

I hope this helps!


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4 years ago
4/7 = ________ (decimal-round to hundredths)
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Step-by-step explanation:

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3 years ago
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A population of values has a normal distribution with μ = 247 and σ = 62.2. You intend to draw a random sample of size n = 16. (
nadya68 [22]

Answer:

a) z = \frac{295.2-247}{62.2}=0.772

And using the normal distribution table or excel we got:

P(Z>0.772) = 1-P(Z

b) z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119

And we can use the normal standard table or excel in order to find the probability and we got:

P(z>3.119) =1-P(Z

Step-by-step explanation:

For this case we know that the random variable of interest is normally distributed with the following parameters:

X \sim N (\mu = 247, \sigma =62.2)

Part a

We want to find this probability:

P(X>295.2)

And we can use the z score formula given by:

z = \frac{X-\mu}{\sigma}

Replacing we got:

z = \frac{295.2-247}{62.2}=0.772

And using the normal distribution table or excel we got:

P(Z>0.772) = 1-P(Z

Part b

We select a random sample of size n = 16 and we try to find this probability:

P(\bar X >295.2)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119

And we can use the normal standard table or excel in order to find the probability and we got:

P(z>3.119) =1-P(Z

8 0
3 years ago
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