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dlinn [17]
3 years ago
10

Which values are solutions? check all that apply HELP PLEASE

Mathematics
1 answer:
Ivenika [448]3 years ago
4 0
Square both sides of the inequality:
  x > 81

A, C, F are numbers that are greater than 81.
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The campers in cabin C walked 3/5 of 9 miles. how many miles did they walk?
kobusy [5.1K]
3/5×9
(3×9)/5
27/5=25/5+2/5
5 2/5
5.4 miles
7 0
4 years ago
PLEASE NEED HELP NOW WILL GIVE BRAINLIEST<br> What is the value of B?
Tresset [83]
So all the angles of triangle add up to 180 degrees. So you add up the the two other sides and subtract 180 by the answer.

61 + 58 = 119

180 - 119 = 61

So, you’re answer would be 61 degrees. Hope that helped :)

8 0
3 years ago
A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the
hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0
3 years ago
Challenge #1
o-na [289]

Answer:

Translate 10 units right, 9 units up

Step-by-step explanation:

translations simply take the image and move it up or down or side to side, reflections flip the image, dilation changes the dimensions of an image, and rotation rotates an image on its origin point.

8 0
3 years ago
How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}&#10;f(x)=\sqrt[3]{7x-2}\\\\&#10;g(x)=\cfrac{x^3+2}{7}&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;now&#10;\\\\&#10;f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}&#10;\\\\\\&#10;\sqrt[3]{x^3}\implies x\\\\&#10;-----------------------------\\\\&#10;or&#10;\\\\&#10;g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}&#10;\\\\\\&#10;\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
8 0
3 years ago
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