Asked and answered elsewhere.
brainly.com/question/10192511Knowing that 1+2i is a root, you also know that 1-2i is a root, so one quadratic factor is
(x -1)² -(2i)² = x^2 -2x +5
Long division of the given polynomial by this quadratic gives a quotient of
x² +9
which has roots ±3i.
Then all
the roots are {-3i, 3i, 1-2i, 1+2i}.
Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3
<u>Solution:</u>
We have been given two equations which are as follows:
3x - 4y = -24 ----- eqn 1
x + 4y = 8 -------- eqn 2
We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.
We rearrange eqn 2 as follows:
x + 4y = 8
x = 8 - 4y ------eqn 3
Now we substitute eqn 3 in eqn 1 as follows:
3(8 - 4y) -4y = -24
24 - 12y - 4y = -24
-16y = -48
y = 3
Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:
x = 8 - 4(3)
x = 8 - 12 = -4
Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.
(-3,4)(0,-3)
slope = (-3 - 4) / (0 - (-3) = -7/3 <=
Answer:
12/40 (simplified = 3/10)
Step-by-step explanation:
2 x 6 = 12
5 x 8 = 40
U = 1
L = 0
R = -2
I = 24
M = 17
H = -3
E = 100
S = -439
O = 11
B = -6
T = -41
D = 19
C = 206
<em>Hope this helped ! :)</em>
