Hi☺️ i think it is around the number of less than 2
hope this help !
Step 1
<u>Find the value of TS</u>
we know that
if PQ is parallel to RS. then triangles TRS and TPQ are similar
so
solve for TS
we have
substitute
Step 2
<u>Find the value of SQ</u>
we know that
we have
substitute
therefore
<u>the answer is</u>
the value of SQ is 
First, distribute the 100 to the (x-1) portion:
500 = 100x - 100
then, add 100 to both sides of your equation to get “x” alone on the right side:
500 + 100 = 100x - 100 + 100
600 = 100x
next, divide 100x by 100 and 600 by 100 to isolate a singular “x”:
600/100 = 100x/100
6 = x
therefore, x=6 is your solution
Answer:
slope = 1
m = 1
Step-by-step explanation:
We count rise over run = 1/1
m = 1
y = x
Answer:
Variance = 1,227.27
Standard deviation = 35.03
Step-by-step explanation:
To calculate these, we use the following formulas:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
Standard deviation = Variance^0.5
Where;
n = number of values = 20
x = each value
Therefore, we have:
Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674
Mean = 1,674 / 20 = 83.70
Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27
Standard deviation = 1,227.27^0.5 = 35.03
