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balandron [24]
3 years ago
13

The fifth grade students 15/20 went to the book fair of the students who went to the book fair 12/16 bought at least one book wh

at fraction grade students boucht at least one book show your work
Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

\frac{9}{16}

Step-by-step explanation:

Out of a total of 1,  \frac{15}{20}  went to the fair and  \frac{12}{16} OF THOSE, bought atleast one book.

To find the fraction of students who bought at least one book, we will multiply both the fractions. That is the answer. Shown below:

\frac{15}{20}*\frac{12}{16}\\=\frac{3}{4}*\frac{3}{4}\\=\frac{9}{16}

Answer is  \frac{9}{16}

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The angle of depression from the top of a building to a point
AleksandrR [38]

The distance between point on the ground from the top of the building is 396 meter, if the building is 280 m high and The angle of depression from the top of a building to a point  on the ground is 45 degrees.

Step-by-step explanation:

The given is,

                 The angle of depression from the top of a building to a point  on the ground is 45 degrees.

                 Height of the building is 280 meter.

Step: 1

                 Given diagram is a right angled diagram,

                 For right angle triangle,

                              90° = 45° + 45°    

                                     = 90°  

                 Trignometric ratio,

                            sin ∅ = \frac{Opp}{Hyp}....................(1)

                For the above ratio take the bottom angle, that is angle of depression from the top of a building to a point  on the ground is 45 degrees.

                 Where, Opp side = 280 meters

                               Hyp side = x

                                           ∅ = 45°

                 Equation (1) becomes,

                                  sin 45° = \frac{280}{x}

                          0.70710678 =  \frac{280}{x}

                                            x =  \frac{280}{0.70710678}

                                            x = 395.979

               Distance between point on the ground from the top of the building,  x ≅ 396 meter                                                

                Trignometric ratio,

                                     cos ∅ = \frac{Adj}{Hyp}

                                   Cos 45 = \frac{Adj}{396}

                                         Adj = (0.70710678)(396)

              Bottom length, Adj = 280 meter

Result:

           The distance between point on the ground from the top of the building is 396 meter.

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