The diagram is attached below
Beaker 1: The measurement line is between 32 and 33. There are 5 lines between 32 and 33. Making line is between third line and fourth line(between 6 and 8). So 32.7
Beaker 2: The measurement line is between 30 and 40. We can clearly see the measurement line at 32. So its 32
Beaker 3: The measurement line is between 32.7 and 32.8. We have 10 small lines inbetween them. Measurement line at 4. So its 32.74
(b) the amount of water in each of 3 beakers are not same because we can measure the difference. But they are close to each other.
Answer:
(5, 3 ) and (- 
, - 10 )
Step-by-step explanation:
Given the 2 equations
2x - y = 7 → (1)
xy = 15 → (2)
Rearrange (1) expressing y in terms of x , that is
y = 2x - 7 → (3)
Substitute y = 2x - 7 into (2)
x(2x - 7) = 15
2x² - 7x = 15 ( subtract 15 from both sides )
2x² - 7x - 15 = 0 ← in standard form
(x - 5)(2x + 3) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 5 = 0 ⇒ x = 5
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
Substitute these values into (3) for corresponding values of y
x = 5 : y = 2(5) - 7 = 10 - 7 = 3 ⇒ (5, 3 )
x = - : y = 2(- ) - 7 = - 3 - 7 = - 10 ⇒ (- , - 10 )
Point-slope equation=y+1=5(x+2)
slope intercept form=5x+9
12. On addition, you can just combine like terms.
2v^3+(-v^3)=v^3
-v+v cancels each other out
8+(-3)=5
So you have v^3+5
14 On subtraction, you have to remember to distribute the negative sign so after you do that you have:
4h^3+3h+1+5h^3-6h+2
Then you can combine like terms
4h^3+5h^3=9h^3
3h-6h=-3h
1+2=3
So you end up with:
9h^3-3h+3
Hope that helps and feel free to ask any questions.
