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patriot [66]
2 years ago
9

Help║...................

Mathematics
2 answers:
disa [49]2 years ago
8 0
66 because it is 180-60+54 which is 66
lions [1.4K]2 years ago
7 0
180-(60+54)=66
So the answer is 66*
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Please need help evaluate the math problems
alina1380 [7]

x + y when x = 6 and y = 2

6 + 2 = 8

\frac{9x+24}{4} when x = 12 and y = 20

\frac{148}{4} = 37

\frac{6m}{n} when m = 12 and n = 3

\frac{72}{3} = 24

Six times x

6x

Six increased by x

6 + x

The sum of x and y

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3 years ago
A tree cast a shadow that is 20 feet long. Frank is 6 feet tall, and while standing next to the tree he cast a shadow that is 4
baherus [9]
A.  So we know that a 6 foot figure casts a shadow 4 feet long.  4 foot shadow x 5 = a 20 foot shadow.  So this means we take 6 x 5 = 30, and the tree is 30 feet tall.  
B.  30 - 6 = 24 feet taller than Frank 
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3 years ago
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Randy works 50 weeks a year, averaging $500 a week in wages. He is offered a salaried position at $27,500 a year. If he accepts
blagie [28]

Answer:

b. more money

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50*500 = $25,000

The new position will let him make:

$27,500

Therefore,

original position < new position = $25,000 < $27,500

3 0
2 years ago
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grigory [225]

Answer:

4.5

Step-by-step explanation:

have a great day

3 0
2 years ago
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A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The
alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

d(t)=-16t^2+48t+160

t is the time

d(t) is the distance traveled

Initial height is 160 feet and initial velocity is 48 ft/sec

If we want to find the time it takes the ball to hit the ground, we let d(t) equal to 0 and find t. Shown below:

-16t^2+48t+160=0\\t^2-3t-10=0\\(t-5)(t+2)=0\\t=5,-2

We disregard t = -2 since time can't be negative. We take t = 5

Thus, after 5 seconds, the ball strikes the ground.

The equation is a quadratic of the form: ax^2+bx+c

Matching equations, we can say:

a = -16

b = 48

c = 160

The time when ball reaches max height is given as:

t=-\frac{b}{2a}

Substituting, we find:

t=-\frac{b}{2a}\\t=-\frac{48}{2(-16)}\\t=1.5

The ball reaches maximum height at t = 1.5 seconds

The max height can be found by putting t = 1.5 into the original equation. Shown below:

d(t)=-16t^2+48t+160\\d(1.5)=-16(1.5)^2+48(1.5)+160\\=196

The max height is 196 feet

8 0
3 years ago
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