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3 years ago

The value of 8 in 800 is how many times as large as the value of 8 in 80

Mathematics

2 answers:

MAVERICK [17]3 years ago

6 0

It is 10 times larger

Romashka [77]3 years ago

5 0

The value of 8 in 800 is 10 x as large as the value of 8 in 80

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Solve GHI. Round the answer to the nearest hundredth.

Sedaia [141]

Answer:

Part 1) $HI=15\ units$

Part 2)

Part 3) $< I=28.07\°$

The answer is the option A

Step-by-step explanation:

Part 1) Find the measure of side HI

Applying the Pythagoras Theorem

$GI^{2} =GH^{2}+HI^{2}$

substitute the values and solve for HI

$17^{2} =8^{2}+HI^{2}$

$HI^{2}=17^{2}-8^{2}$

$HI^{2}=225$

$HI=15\ units$

Part 2) Find the measure of angle G

In the right triangle GHI

$cos(G)=\frac{GH}{GI}$

substitute the values

$cos(G)=\frac{8}{17}$

$G=arccos(\frac{8}{17})=61.93\°$

Part 3) Find the measure of angle I

Remember that

The sum of the interior angles of a triangle must be equal to 180 degrees

substitute the values

$61.93\°+90\°+< I=180\°$

$< I=180\°-(61.93\°+90\°)=28.07\°$

7 0

3 years ago

Simplify the following expression. -16 - 8/2 + 25 ÷ 5 + 1 -18 6 10 -6

Andrews [41]

The answer is -6. Thought there is a chance I am wrong. Need an explanation?

6 0

3 years ago

0.9 (13) - 1.7 (3) =

marissa [1.9K]

Answer:

6.6

Step-by-step explanation:

8 0

3 years ago

Distribute: -3(4a-5b+c)

kvv77 [185]

Answer:

I got it.

Step-by-step explanation:

-12a - (-15b) + (-3c)

4 0

3 years ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

3 0

2 years ago