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3 years ago

13

Find the cube root. 343/64

1 answer:

Leokris [45]3 years ago

5 0

Answer:

28

Step-by-step explanation:

cube root of 343×64=7×4=28

hope this helps UwU

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The length of a rectangle is 4cm longer than the width the perimeter is 80cm. Find the length.

Alenkinab [10]

Answer:

Length = 22cm

Step-by-step explanation:

Perimeter of a rectangle, P = 2(L + W)

Also, from the question, P = 80 cm

Therefore, P = 2(L +W) = 80

The length is 4 cm longer than the width

then, length, L = 4 + W

Slot in the value of L

2 {(4+W) + W} = 80

2(4 + 2W) = 80

8 + 4W = 80

Subtract 8 from both sides

8 - 8 +4W = 80 -8

4W = 72

Divide both sides by the coefficient of W which is 4

W = 18 cm

Recall,

L = 4 + W

L = 4 + 18

L = 22cm

6 0

3 years ago

Which inequality represents all values of x for which the quotient below is<br> defined?

garri49 [273]

Answer:

Option B: x > 0

Step-by-step explanation:

Option A is wrong because $\sqrt{3(0)}$ will be 0. So, the inequality can't be divided by 0.

Option C is wrong because 1 will suffice this inequality. $\sqrt{7}/\sqrt{3}=1.5 (approx)$

Option D is wrong because any value in the root has to be greater or equal to 0 (otherwise, it's imaginary number). -1 will give the latter root a value of root-(-3).

Leaving us with only option B, which is the right answer.

7 0

3 years ago

Please quickly help me!!

Ainat [17]

Look at the picture.

Answer:

$\angle ADB\cong\angle ACB\\\\\angle DAC\cong\angle DBC$

4 0

3 years ago

Fernando followed two diagonal paths, Paths 1 and 2, to get from his house, F, to a neighborhood corner store, C, as shown below

aleksandrvk [35]

Answer:

42 meters

Step-by-step explanation:

Given

See attachment for complete question

Required

Calculate distance FC

FC is calculated as:

$FC = Path\ 1 + Path\ 2$

Where

$Path\ 1 = FB$

$Path\ 2 = BC$

Considering $\triangle FEB$ , we have:

$FB^2 = FE^2 + BE^2$ --- Pythagoras theorem

Where

$FE = FD - BA$

$FE = 22m - 15m$

$FE = 7m$

and

$BE = CD - CA$

$BE = 32m - 8m$

$BE = 24m$

So:

$FB^2 = FE^2 + BE^2$

$FB^2 = 7^2 +24^2$

$FB^2 = 49 +576$

$FB^2 = 625$

Take square roots of both sides

$FB = 25$

So:

$Path\ 1 = 25$

Considering $\triangle BAC$ , we have:

$BC^2 = BA^2 + AC^2$ --- Pythagoras theorem

Where:

$BA = 15$ and $AC = 8$

So, we have:

$BC^2 = 15^2 + 8^2$

$BC^2 = 225 + 64$

$BC^2 = 289$

Take square roots of both sides

$BC = 17$

So;

$Path\ 2= 17$

Recall that:

$FC = Path\ 1 + Path\ 2$

$FC = 25 + 17$

$FC = 42$

6 0

3 years ago

NO LINKS!!! This is NOT MULTIPLE CHOICE!!!

aleksley [76]

Answer:

Given equation: $y=(x+1)^2-2$

The function is a <u>quadratic function</u> in <u>vertex form</u>: $y=a(x-h)^2+k$

<u>Translations</u>

For $a > 0$

$f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}$

$f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}$

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

Parent function: $f(x)=x^2$

<u>Translations</u>

Translated 1 unit left: $f(x+1)=(x+1)^2$

Then translated 2 units down: $f(x)-2=(x+1)^2-2$

Therefore, translate the parent function by <u>1 unit left</u> and <u>2 units down</u> to produce the given equation.

4 0

3 years ago

Read 2 more answers