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Readme [11.4K]
3 years ago
5

I will thank you!!!!

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
What question do you need help on?
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Simplify 2^9 divided by 2^6 I need help ASAP can you help me pleaseee
sveta [45]

Answer:

8

Step-by-step explanation:

3 0
3 years ago
Simplify the expression -3 + 1/3 x + (-4.5) - 1/5x
WITCHER [35]

Answer:

Step-by-step explanation:

-3 +\dfrac{1}{3}x - 4.5 -\dfrac{1}{5}x\\\\\\= -3 - 4.5 +\dfrac{1}{3}x - \dfrac{1}{5}x\\\\\\= - 7.5 + \dfrac{1*5}{3*5}x - \dfrac{1*3}{5*3}x\\\\\\= -7.5 +\dfrac{5}{15}x-\dfrac{3}{15}x\\\\\\= -7.5 + \dfrac{5-3}{15}x\\\\\\= -7.5 +\dfrac{2}{15}x

6 0
2 years ago
Read 2 more answers
50 POINTS!!!!
Softa [21]

Answer:

Step-by-step explanation:

Given that X -  the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.

Height of male pilot = 74.2 inches

We have to find the percentile

X = 74.2

Corresponding Z score = 74.2-72.6 = 1.6

P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%

i.e. only 5% are below him in height.

Thus the malepilot is in 5th percentile.

3 0
1 year ago
True or False? The graph of sine can be used to construct the graph of the secant function.
amid [387]

True

Note that:

secant \theta = \frac{1}{cos\theta}

The graph of sine and cosine functions are very similar. They only have a shift in the x -axis.

That is,  sin x  =  cos (90  -  x)

Since there is a great similarity between the sine and cosine graphs, and the secant graph is an inverse of the cosine graph, the graph of sine can be used to construct the graph of the secant function

Mathematically:

since  sec x  =  1 / cos x

and, cos x = sin (90 - x)

therefore, sec x = 1 / sin (90 - x)

The graphs of the sine and secant functions are attached to this solution

Learn more here: brainly.com/question/9554579

5 0
3 years ago
Please help me thank you so much. Just not sure of my answers
Sedaia [141]

Answer:

An interesting experiment is given. We need to address various questions based on our knowledge of calculus.

Step 2

Part (a)

Time taken for the radius to grow to 2 cm = t1 = r/0.5 = 2/0.5 = 4 hours

Time taken for the radius to become 0 = t2 and the same can be obtained by solving:

r = 2 - √t2 = 0

Hence, t2 = 22 = 4 hours

Hence, the time duration of the entire experiment (from the introduction of the bacteria until its disappearance) = t1 + t2 = 4 + 4 = 8 hours

Step 3

Part (b)

r(t) = 0.5t for 0 ≤ t ≤ 4

and

r(t) = 2 - √(t - 4) for t > 2

Step-by-step explanation:

7 0
3 years ago
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