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Readme [11.4K]
3 years ago
5

I will thank you!!!!

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
What question do you need help on?
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In a candy factory, nutty chocolate bars contain 22.0% by mass pecans. If 4.5 kg of pecans were used for candy last Tuesday, how
Zanzabum
So we know that 22% of the mass off the chocolate bars is pecans, and that 4.5kg of pecans were used. To find the mass of nutty chocolate bars made with 4.5kg of pecans we can divide the 4.5 by 22 to find 1% of the weight of nutty chocolate bars produced, then multiply it by 100 to find the full weight in kg.

So 4.5/22= 0.205 (3dp), then 0.205x100=20.5kg of nutty chocolate bars produced.

Now to convert the kgs of chocolate bars to lbs, we multiply by 2.205 (as there is approximately 2.205 lbs to 1 kg).

So 2.205x20.5kg=45.203 lbs (3dp) of nutty chocolate bars produced on Tuesday.
4 0
3 years ago
Please help 20 POINTS. Problem is below!!
Helga [31]

10 units up means to add 10 to the y-coordinate of the vertex (h, k).

p(x) = 0.005(x - 40)² + 60

p(x) shifted up 10 units = 0.005(x - 40)² + (60 + 10)

                                q(x) =  0.005(x - 40)² + 70  


6 0
4 years ago
Solve the following equation.<br><br> 5x+23=53<br><br> A) x=5<br> B) x=6<br> C) x=1<br> D) x=7
Zolol [24]

Answer:

6

Step-by-step explanation:

5×+23= 53

5×+23-23= 53-23

5x=30

30÷5=6

6 0
3 years ago
Read 2 more answers
How to work out 18000÷120 on paper
GaryK [48]

Answer:

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(b) Use the right-hand rule to decide whether the components of a × b are positive, negative, or 0.
Gekata [30.6K]

(a)

Given:  

\vec{a} is in xy plane and \vec{b} is in the direction of k.

|a|=6 units, |b|=3 and θ = 90°

|a × b| = |a| × |b| sinθ  

          = |a| × |b| sin90°  

          = 6 × 3 × 1  

|a × b| = 18  

(b)

Let \vec{c}=\vec{a} \times \vec{b}

\vec{c} is perpendicular to both \vec{a} \text { and } \vec{b}.

In this case,

x-component of \vec{a} \times \vec{b} is positive.

y-component of \vec{a} \times \vec{b} is negative.

z-component of \vec{a} \times \vec{b} is zero.

5 0
3 years ago
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