12.568% is the correct answer
Answer:
P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.
Step-by-step explanation:
P and Q are the intersection points of
x-y+1 = 0 and the circle x^2 + y^2 = 25
sub y = x+1 into the circle
x^2 + (x+1)^2 = 25
x^2 + x^2 + 2x + 1 - 25 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = 3 or x = -4
y = 4 or y = -3
so P(3,4) and Q(-4,3) are our two points
Height of triangle.
h = |0 - 0 + 1|/√2 = 1/√2
PQ = √( (-7)^2 + 1^2) = √50 = 5√2
area POQ = (1/2)(1/√2)(5√2) = 5/2 square units
hope this helped
Answer:
x=-7/9
y = 12/9
Step-by-step explanation:
6x + 2y = -2
3x - 2y = -5
9x = -7 (-2y and +2y eliminated)
x = -7/9
if 3x -2y = -5 then
3 ×(-7/9) -2y =-5➡
-21/9 -2y = -5➡
-2y = -5 + 21/9
-2y = -24/9
Answer:
9^6
Step-by-step explanation:
When dividing exponents with the same base, we subtract the exponents
a^b/ a^c = a^(b-c)
9^11/9^5 = 9^(11-5)
= 9^6
putting all the names in a hat and selecting six students because no one knows which names are going to be pulled out.
