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2 years ago

Solve 1/8^-1/3 Write in fraction form plz. :)

Mathematics

1 answer:

sladkih [1.3K]2 years ago

7 0

Answer:

$\frac{1} {2^{-1}}$

Step-by-step explanation:

$\huge \frac{1}{ {8}^{ - \frac{1}{3} } } \\ \\ = \huge \frac{1}{ {( {2}^{3} )}^{ - \frac{1}{3} } } \\ \\ = \huge \frac{1}{ {{2} }^{ - 3 \times \frac{1}{3} } } \\ \\ = \huge \frac{1}{ {{2} }^{ - 1 } }$

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2 years ago

What would i use to factor 15x^2+10x-9x-6

boyakko [2]

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2 years ago

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mario62 [17]

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2 years ago

If f(x) = x/2 plus 8 what is f(x) when x = 10

kicyunya [14]

$f(x)=\frac{x}{2}+8$

Given y = f(x)

Substitute x = 10.

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Therefore f(x) = 13 when x = 10

5 0

2 years ago

I need help with this

evablogger [386]

Answer:

A) (-8, -16)

B) (0, 48)

C) (-4, 0), (-12, 0)

Step-by-step explanation:

A) the vertex is the minimum y value.

extremes of a function we get by using the first derivation and solving it for y' = 0.

y = x² + 16x + 48

y' = 2x + 16 = 0

2x = -16

x = -8

so, the vertex is at x=-8.

the y value is (-8)² + 16(-8) + 48 = 64 - 128 + 48 = -16

B) is totally simple. it is f(0) or x=0. so, y is 48.

C) is the solution of the equation for y = 0.

the solution for such a quadratic equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case here

a=1

b=16

c=48

x = (-16 ± sqrt(16² - 4×48)) / 2 = (-16 ± sqrt(256-192)) / 2 =

= (-16 ± sqrt(64)) / 2 = (-16 ± 8) / 2 = (-8 ± 4)

x1 = -8 + 4 = -4

x2 = -8 - 4 = -12

so the x- intercepts are (-4, 0), (-12, 0)

6 0

2 years ago