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2 years ago

Calculating interests,plz help-

Mathematics

1 answer:

madam [21]2 years ago

8 0

HELLOOOOOOOOOOOOOOOOOOOOOOOOOOOOO :D

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Problem Ari thinks the perfect milkshake has 333 ounces of caramel for every 555 scoops of ice cream. Freeze Zone makes batches

Diano4ka-milaya [45]

Answer:

That their milkshakes need more caramel or less ice cream.

Step-by-step explanation:

We can see that Ari's numbers for a perfect milkshake gives us a caramel to ice cream ratio of 333 / 555 = 0,6.

But the Freeze Zone uses a caramel to ice cream ratio of 666 / 888 which is equal to 0,75.

Their milkshakes have less caramel and more ice cream than Ari's perfect milkshake so Ari will think that Freeze Zone's milkshakes are not sweet enough.

I hope this answer helps.

8 0

2 years ago

Solve this system of equations: X=? Y=? ( JUST WRITE THE NUMBER ANSWERS WITH A COMMA BETWEEN THEM)

hjlf

Answer:

Therefore the Final Solution is

x = 2 and y = 4

( 2 , 4 )

Step-by-step explanation:

Given:

$y=2x$ ...............Equation ( 1 )

$x=-y+6$ ................Equation ( 2 )

To Find:

x = ?

y = ?

Solution:

Substitute Equation ( 1 ) in Equation ( 2 ) we get

$x=-2x+6\\\\3x=6\\\\3x=6\\\\x=\frac{6}{3} \\\\\therefore x =2$

Now Substituting x = 2 in Equation ( 1 ) we get

$y =2\times 2\\\\\therefore y=4$

Therefore the Final Solution is

x = 2 and y = 4

( 2 , 4 )

4 0

3 years ago

0.5(70a + 12b +2)<br> anyone??

gregori [183]

THE ANSWER IS 49ab BECAUSE YEAH

4 0

2 years ago

Read 2 more answers

I need help with answers 5-11

Shtirlitz [24]

-6 is the correct answer

6 0

3 years ago

How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.

stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula $\displaystyle nCr=\frac{n!}{r!(n-r)!}$ which describes the number of ways we can choose $r$ objects given $n$ possible choices. So, if $n=7$ and $r=4$ , then:

$_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35$

Hence, the teacher can make 35 different geometry quizzes.

3 0

2 years ago