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3 years ago

10

Guys help me ASAP RANDOM ANSWERS WILL BE MODERATED! Thanks

1 answer:

GalinKa [24]3 years ago

7 0

18) the answer is 3 because CD is a segment bisector that seperates both AB and BD into 2 congruent segments.And perpendicular lines form right angles.

19) the answer is 1 because the S represents AB is congruent to BD. Then, A represents the right angles: angle ADC and angle BDC. Lastly. S is represented by the common side which is segment CD.

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When solving an equation, Carmen's first step is shown below. Which property justifies Carmen's first step? plz help me

Damm [24]

Answer:

the addition property of equality

Step-by-step explanation:E

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3 years ago

Inverse Function In Exercise,analytically show that the functions are inverse functions.Then use the graphing utility to show th

Anna [14]

Step-by-step explanation:

We need to show whether

$f^{-1}(x) = g(x)$

or

$g^{-1}(x) = f(x)$

so we'll do either one of them,

we'll convert f(x) to f^-1(x) and lets see if it looks like g(x).

$f(x) = e^x - 1$

we can also write it as:

$y = e^x - 1$

now all we have to do is to make x the subject of the equation.

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$\ln{(y+1)} = x$

$x=\ln{(y+1)}$

now we'll interchange the variables

$y=\ln{(x+1)}$

this is the inverse of f(x)

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and it does equal to g(x)

$g(x)=\ln{(x+1)}$

Hence, both functions are inverse of each other!

This can be shown graphically too:

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3 years ago

I need some help on my hw! Find the area

Andrej [43]

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3 years ago

Read 2 more answers

PLEASE HELP ASAP <br>are f(x)=4/x-2-1 and g(x)=3/x+2-2 inverses of each other?

GREYUIT [131]

Answer:

To find the inverse of:

$f (x)=\dfrac{4}{x-2}-1$

Set the function to y:

$\implies y=\dfrac{4}{x-2}-1$

Rearrange to make x the subject:

$\implies y+1=\dfrac{4}{x-2}$

$\implies (y+1)(x-2)=4$

$\implies xy-2y+x-2=4$

$\implies xy+x=2y+6$

$\implies x(y+1)=2y+6$

$\implies x=\dfrac{2y+6}{y+1}$

Swap x and y:

$\implies y=\dfrac{2x+6}{x+1}$

Change y to the inverse of the function sign:

$\implies f$ $\:^{-1}(x)=\dfrac{2x+6}{x+1}$

Rewrite g(x) as a fraction:

$g(x)=\dfrac{3}{x+2}-2$

$\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2x-4}{x+2}$

$\implies g(x)=-\dfrac{2x+1}{x+2}$

Therefore, as the inverse of f(x) ≠ g(x), the functions are NOT inverses of each other

4 0

2 years ago

Justine answered 68 questions correctly on an 80-question test. Express this amount as a fraction,percent, and decimal.

kenny6666 [7]

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3 years ago

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