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3 years ago

Find the solution b = 2/3 a + 1

Mathematics

1 answer:

siniylev [52]3 years ago

4 0

Answer:

2a/3 + 1

Step-by-step explanation:

Combine multiplied terms into a single fraction-

2/3 a + 1

2a/3 + 1

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The area of rhombus is 360cmsquare and one of its diagonalis 18cm. Find the other diagonal.

Yanka [14]

Answer: 40 cm

So the diagonal formula is - 1/2* (d1*d2) d1 is the first diagonal and d2 is the second diagonal.

So,

1/2 * (18*d2)= 360

18*d2= 360*2

d2= 720/18

d2= 40

6 0

3 years ago

A) how many men have a waist measurement of more than 85 cm

KATRIN_1 [288]

Answer:

(a)29

(b)91cm

Step-by-step explanation:

(a)From the graph, 11 men have a waist measurement of 85cm and below.

Since the cumulative frequency is 40

Number of men who have a waist measurement of more than 85 cm

$=40-11\\=29$

(b)Median

$\text{Median}=\dfrac{N}{2}\\N=40\\Median=\dfrac{40}{2}=20th$ item$

Tracing 20 from the y-axis to the x-axis, the median waist measurement is 91cm.

(c)Interquartile Range

Interquartile Range = $Q_3-Q_1$

$Q_1=\dfrac{N}{4}=\dfrac{40}{4}=10th$ item$

From the graph, at y=10, x=84 cm

$Q_3=\dfrac{3N}{4}=\dfrac{3*40}{4}=30th$ item$

From the graph, at y=30, x=97 cm

Therefore:

Interquartile Range=97-84=13cm

5 0

3 years ago

If 54% of all people between the ages of 35 and 50 ride a bike, find the probability for a sample of 30 people in that age group

Yuliya22 [10]

Answer:

The probability is 0.1312

Step-by-step explanation:

Here, let us set up a binomial system

From the question, 54% ride a bike

Let p = people that rides a bike

54% = 54/100 = 0.54

p = 0.54

q = 1 - p = 1 -0.54 = 0.46 ( 46% do not ride bikes)

Now, for the binomial system, we have

P(X = 15) = 30 C 15 • p^15•q^15

We have;

30 C 15 * 0.54^15 * 0.46^15

= 0.131200268998

The probability is 0.1312

8 0

3 years ago

Will give brainiest In △ABC, angle bisectors

EleoNora [17]

Answer:

$m\angle CAB=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=25\dfrac{5}{7}^{\circ}$

Step-by-step explanation:

AK is angle A bisector, then

$m\angle BAK=m\angle KAC=x^{\circ}$

BL is angle B bisector, then

$m\angle ABL=m\angle CBL=y^{\circ}$

Consider triangle ABL. The sum of the measures of all interior angles in this triangle is $180^{\circ},$ then

$m\angle BAL+m\angle ALB+m\angle LBA=180^{\circ}\\ \\2x+2y+y=180\\ \\2x+3y=180$

Consider triangle ABK. In this triangle,

$m\angle AKB=180^{\circ}-2x^{\circ} \ [\text{Supplementary angles}]$

The sum of the measures of all interior angles in this triangle is $180^{\circ},$ then

$m\angle BAK+m\angle AKB+m\angle KBA=180^{\circ}\\ \\x+(180-2x)+2y=180\\ \\2y-x=0$

Hence,

$x=2y\\ \\2(2y)+3y=180\\ \\4y+3y=180\\ \\7y=180\\ \\y=\dfrac{180}{7}=25\dfrac{5}{7}\\ \\x=\dfrac{360}{7}=51\dfrac{3}{7}$

Find the measures of the triangle ABC:

$m\angle CAB=2x^{\circ}=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=2y^{\circ}=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=180^{\circ}-102\dfrac{6}{7}^{\circ}-51\dfrac{3}{7}^{\circ}=25\dfrac{5}{7}^{\circ}$

8 0

4 years ago

What divided by 63 equals 9

erastovalidia [21]

The answer is 7.

there you go!

8 0

3 years ago

Read 2 more answers

Find the solution b = ￼2/3 a + 1

Find the solution b = 2/3 a + 1