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3 years ago

Find the solution b = 2/3 a + 1

Mathematics

1 answer:

siniylev [52]3 years ago

4 0

Answer:

2a/3 + 1

Step-by-step explanation:

Combine multiplied terms into a single fraction-

2/3 a + 1

2a/3 + 1

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Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr

drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

$AC^2= AB^2+BC^2$

$\Rightarrow (x+3)^2=x^2+8^2$

$\Rightarrow x^2+6x+9=x^2+64$

$\Rightarrow 6x=64-9=55$

$\Rightarrow x=55/6=9.17$ chi.

Hence, the height of the pole, $AB=x=9.17$ chi,

and the length of the rope, $x+3=9.17+3=12.17$ chi.

8 0

3 years ago

What is 0.5 + -1 1/2

lakkis [162]

-1 is your answer.........

6 0

3 years ago

Help pleaseeeeeeeeee

sergij07 [2.7K]

9514 1404 393

Answer:

47 -6√10

Step-by-step explanation:

As you know, the area of a square is the square of the side length. It can be helpful here to make use of the form for the square of a binomial.

(a -b)² = a² - 2ab + b²

(√2 -3√5)² = (√2)² - 2(√2)(3√5) + (3√5)²

= 2 - 6√10 + 3²(5)

= 47 -6√10

<em>Check</em>

√2-3√5 ≈ -5.29399 . . . . . . . . note that a negative value for side length makes no sense, so this isn't about geometry, it's about binomials and radicals

(√2-3√5)² ≈ 28.02633

47 -6√10 ≈ 28.02633

5 0

3 years ago

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

7 0

3 years ago

How do you add mixed fractions?

ycow [4]

If u have 4\3 and 4\5 u add 4+4=8 and then do 5+3=8 and now you have 8\8 and that is how to add ixed fractions

3 0

3 years ago

Find the solution b = ￼2/3 a + 1

Find the solution b = 2/3 a + 1