Solve this and explain!!!

A regular triangular pyramid has slant height 6 cm and base edges of length 15 cm. Find: Volume and surface area of the pyramid

just olya [345]

Step-by-step explanation:

the number of members in A municipal corporation depends upon the _______ city

7 0

3 years ago

write an equation for the line passing through the point (3,5) and perpendicular to the line y=-1/3x+5

jarptica [38.1K]

Answer:

y= 3x -4

Step-by-step explanation:

The equation of a line can be written in the form of y=mx +c, where m is the slope and c is the y-intercept. This is also known as the slope-intercept form.

$y = - \frac{1}{3} x + 5$

Since the given equation is in the slope-intercept form, we can identify its slope from the coefficient of x.

Slope= -⅓

The product of the slopes of perpendicular lines is -1.

Slope of perpendicular line

$= - 1 \div ( - \frac{1}{3} )$

$= - 1 \times ( - \frac{3}{1} )$

= 3

Thus, the equation of the perpendicular line is given by:

y= 3x +c

Substitute a pair of coordinates that the line passes through to find the value of c.

When x= 3, y= 5,

5= 3(3) +c

5= 9 +c

<em>Minus 9 on both sides:</em>

c= 5 -9

c= -4

Hence, the equation of the perpendicular line is y= 3x -4.

Additional:

For more questions on equation of perpendicular lines, do check out the following!

brainly.com/question/2141803

4 0

1 year ago

Which quadratic regression equation best fits the data set?

g100num [7]

The 4th selection is appropriate.

_____
Desmos.com has a wonderful graphing calculator. They also have apps for Android and iOS phones and tablets. Of course, your TI-83/84 or equivalent will do this, too.

7 0

3 years ago

Read 2 more answers

an projectile is launched upward with a velocity of 256 feet per second from the top of a 35 foot structure. what is the maximum

Anettt [7]

1052.64 feet

Step-by-step explanation:

Step 1:

Given,

The projectile is launched upward with a velocity of 256 feet per second

The height of the structure is 35 foot.

Step 2 :

The velocity becomes 0 at the highest point.

The equation of motion is v² = u² +2as

where

v represents the final velocity

u represents the initial velocity

a represents the acceleration due to gravity

s is the height

Step 3:

Here we have

u = 256 feet/sec

v = 0

a = -32.2 feet/sec²

Substituting in the above equation, we have

0 = 256² + 2 *(-32.2) *s

=> -64.4 s = -65536

= > s = 65536/64.4 = 1017.64 feet

Hence the projectile travels 1017.64 feet from the top of the structure. Since the height of the structure is given as 35 feet, the maximum height attained by the projectile is 1017.64 +35 = 1052.64 feet

8 0

3 years ago

Jalisa needs to purchase a cover for her oval shaped pool.The pools length and width measurements,as marked by dotted lines are

Brums [2.3K]

Answer:

the area of the cover will be

$933.17ft^{2}$