So first game
half were eliminated
we notice a pattern
first game=64 times 1/2
next game 32 times 1/2 so
so just multiply by 1/2 till you get 1
round 1 64/2=32
round 2 32/2=16
round 3 16/2=8
round 4 8/2=4
round 5 4/2=2
round 6 2/2=1
6 is the answer
If the recursive formula is a(n)=a(n-1)+3 and a1=2 then the explicit formula is:
a(n)=2+3(n-1) which simplifies to
a(n)=2+3n-3
a(n)=3n-1 so the first three terms are a(1), a(2), and a(3) which are:
2, 5, and 8
Given Information:
Probability of super event = P(S) = 0.0023
Number of suppliers = n = 3
Probability of unique event = P(U) = 0.014
Required Information:
Probability that all three suppliers will be disrupted = ?
Answer:
P(3) = 0.0023
Step-by-step explanation:
We want to find out the approximate probability that all three suppliers will be disrupted at the same time at some point during the next five years.
The required probability is given by
P(n) = P(S) + (1 - P(S))*P(U)ⁿ
Where P(S) is the probability of super event that will disrupt all suppliers, P(U) is the probability of unique event that would disrupt one of the suppliers and n is the number of suppliers.
P(3) = 0.0023 + (1 - 0.0023)*(0.014)³
P(3) = 0.0023 + (0.9977)*(0.014)³
P(3) = 0.0023
The correct option is C = 0.0023
Therefore, there is 0.23% probability that all three suppliers will be disrupted at the same time at some point during the next five years.
Answer:
minus 5 by 7
Step-by-step explanation:
5 - 7 = -2
2 - 3 = -1
The smaller the negative integer, the bigger the number.
5x3 + 5x2 - 19 is the answer