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aalyn [17]
3 years ago
8

Lara charges $12 per hour for babysitting. If f represents Lara's total fee after babysitting for h hours, which answer choice s

hows two correct equations that could be used to model the problem?
A: f=112handh=12f
B: h=112fandf=12h
C: f=h+12andh=f−12
D: h=f+12andf=h−12
Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

Can't really read that but these would work

f = 12h

h = f/12

Step-by-step explanation:

You might be interested in
A metal conduit will be used as a pathway for wiring through a concrete block. The conduit is a 5 foot long rod with an outer di
kolbaska11 [484]

Answer:  586.59 cubic centimeters .

Step-by-step explanation:

As per given . we have

Inner diameter =  1.8 inches

⇒Inner radius :r = 0.9 in.  (radius is half of diameter)

= 0.9 x (2.54) = 2.286 cm  [∵ 1 in . = 2.54 cm]

Outer diameter = 2 inches

⇒Outer radius : R = 1 inch  = 2.54 cm

Height : h = 5 feet = 5 x(30.48) = 152.4 cm   [∵  1 foot = 30.48 cm]

The formula to find the volume of a hollow cylinder :

V=\pi(R^2-r^2)h , where R= outer radius , r= inner radius and h= height.

Now , the volume of metal in the conduit :

V=(3.14)(( 2.54)^2-(2.286)^2)(152.4)

V=(3.14)(6.4516-5.225796)(152.4)

V=(3.14)(1.225804)(152.4)

V=586.591342944\approx586.59\ cm^3

Hence, the volume of metal in the conduit is 586.59 cubic centimeters .

5 0
3 years ago
I need help with 8-11....
MaRussiya [10]
8. Quadrants
9. Proportion
10. Proportionality
11. Dimensional analysis
8 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
Subtract -2x^2+4x-1−2x
vivado [14]

Answer:

8x²- x -8

Step-by-step explanation:

The question is not well written. I guess what you mean is:

Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).

To  subtract -2x^2+4x-1 from 6x^2+3x-9, that is

6x^2+3x-9 - (-2x^2+4x-1). This can be written as

6x²+3x-9 - (-2x²+4x-1)

Now, opening the bracket, we will get

6x²+3x-9 +2x²-4x+1

Then, collecting like terms, we get

6x²+2x²+3x-4x-9+1

6x²+2x² = 8x²

3x-4x = -x

-9+1 = -8

∴6x²+2x²+3x-4x-9+1 becomes

8x²-x -8

The answer is 8x²-x -8.

7 0
3 years ago
PLEASE HELP MEEEEEEEEEEEEEEEEEE!!!!!!!!
victus00 [196]
F = 41
E = 90
D = 49
from D to E is 55
then E to F also known as X = 36.08 or 41.51
6 0
3 years ago
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