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Kaylis [27]
2 years ago
15

Solve the simultaneous equations by substitution x − y = 8, x + 4y = 13

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
4 0

Answer:

x = 9; y = 1

Step-by-step explanation:

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Help please and thank you
Sidana [21]

Answer:

It's discrete and non-linear

Step-by-step explanation:

it is not continuous and linear because it does not form a line going in one direction the entire time

6 0
3 years ago
Suppose you invest $750.00 in a fund earning 6% simple discount. A certain time later you withdraw the investment (principal and
barxatty [35]

Answer:

4.08 + 2 = 6.08 years

Step-by-step explanation:

we know that

Simple Interest(S.I.) = (P × R × T) ÷ 100

where, P = Principal = 750

R = Rate = 6%

T = unknown

⇒ S.I. = (750 × 6 × t)÷ 100

⇒ S.I. = 45t

Also, Amount = S.I + Principal

⇒ Amount = 750 + 45t

Now Formula for Compound Interest is:

A = P(1+\frac{r}{100})^{t}

where A = Amount

=1000

P = Principle

r = rate

t = total number of year

Here, P = 750 + 45t, r = 3.5% , and t = 2.

Putting all these values in above formula:

1000 = (750 + 45t)(1+\frac{3.5}{100})^{2}

⇒ 1000 = (750 + 45t)(1.071)

⇒ t = 4.08

Hence, total time required will be 2 + 4.08 = 6.08 years.

7 0
3 years ago
Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7
r-ruslan [8.4K]
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
6 0
4 years ago
Help PLEASESSS due in 20
kicyunya [14]
  1. 4 - 4 + 4 ÷ 4
  2. 4 ÷ 4 + 4 ÷ 4
  3. (4 + 4 + 4) ÷ 4
  4. √4 + √4 + 4 - 4
  5. √4 + 4 + 4 ÷ 4
  6. √4 + 4 + 4 - 4
  7. 4 + 4 - 4 ÷ 4
  8. 4 + 4 + 4 - 4
  9. 4 + 4 + 4 ÷ 4
  10. √4 + √4 + √4 + 4
  11. 44/(√4 + √4)
  12. √4 + √4 + 4 + 4
  13. 44/4 + 4
  14. 4 + 4 + 4 + √4
  15. 44/4 + 4
  16. 4 * 4 * 4 ÷ 4
  17. 4 * 4 + 4 ÷ 4
  18. 4 * 4 - √4 + 4
  19. 4! - 4 - 4 ÷ 4
  20. 4 * (4 + 4 ÷ 4)
  21. 4! - 4 + 4 ÷ 4
  22. 4 * 4 + 4 + √4
  23. 4! - √4 + 4/4
  24. 4 * (√4 + √4 + √4)
  25. 4! + √2 - 4 ÷ 4
  26. 4! + √4 + 4 - 4
  27. 4! + √4 + 4 ÷ 4
  28. 4! + 4 + 4 - 4
  29. 4! + 4 + 4 ÷ 4
  30. 4! + √4 + √4 + √4

Lol, that took a while, hope it helps!

7 0
3 years ago
3a2+4b for a=2 and b=3
Kobotan [32]
First you’ll multiply to get 3x2x2 + 4x3. Then add them together. 12+12=24
4 0
3 years ago
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