Jada had read 2/3 of a book . She has read 60 pages so far . How many pages are in the whole book?

Analyze the diagram below and complete the instructions to follow. Find a, b and c

Feliz [49]

Answer/Step-by-step explanation:

✔️Using trigonometric ratio, find b:

Reference angle = 45

opposite = 8

Hypotenuse = b

Thus,

Sin(45) = 8/b

b = 8/sin(45)

b = 8/(1/√2) (sin 45 = 1/√2)

b = 8 × √2/1

b = 8√2

✔️Find a using trigonometric ratio:

Reference angle = 60°

Hypotenuse = b = 8√2

Adjacent = a

Therefore,

Cos(60) = a/8√2

8√2*cos(60) = a

8√2*½ = a

4√2 = a

a = 4√2

✔️Find c using Pythagorean Theorem:

c² = b² - a²

c² = (8√2)² - (4√2)²

c² = 128 - 32

c² = 96

c = √96

c = √(16*6)

c = 4√6

5 0

2 years ago

HELP ME PLEASEEEEEEEEE

OLga [1]

Answer:

is it 56 units²? if not sorry

4 0

3 years ago

Use the substitution method to solve the system of equations. x+y=11 -x=-y-9

allochka39001 [22]

<h2>Answer:</h2>

Like you said, we need to use substitution to solve for y.

$x + y = 11\\-1(-x = -y - 9)\\\\x + y = 11\\x = y + 9\\\\y + 9 + y = 11\\\\2y + 9 = 11\\\\2y = 20\\\\y = 10$

Now that we've solved for y, we can plug in the number we got into one of the original equations. (You can choose either equation, but I will use the first one.)

$x + 10 = 11\\\\x = 1$

Now we have the solution of this system.

$(1, 10)$

4 0

2 years ago

A 2-column table with 7 rows. Column 1 is labeled sample with entries 1, 2, 3, 4, 5, 6, 7. Column 2 is labeled Sample Mean with

Rom4ik [11]

Answer:

(B)136

Step-by-step explanation:

Edg 2020 your welcome luv <3

7 0

2 years ago

Read 2 more answers

△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km

Anarel [89]

Answer:

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

MK = $\frac{40\sqrt{3}}{1+\sqrt{3}}$ = 25.36

Explanation:

According to the Law of Sines:

$\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}$

where:

A, B, and C are angles

a, b, and c are the sides opposite to the angles

First of all, let's find m∠L: the sum of the angles of a triangle is 180°, therefore

m∠K + m∠L + m∠M = 180°

m∠L = 180° - m∠K - m∠M

m∠L = 180° - 105° - 30°

m∠L = 45°

Now, we can apply the Law of Sines to our case (see picture attached):

$\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}$

Let's solve one side at the time:

$\frac{LM}{sinK}=\frac{MK}{sinL}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{MK}{sin(45)}$

$MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)$

MK = $\frac{40\sqrt{3} }{1+\sqrt{3} }$ = 25.36

Similarily:

$\frac{LM}{sinK}=\frac{KL}{sinM}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{KL}{sin(30)}$

$KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)$

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

8 0

3 years ago