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3 years ago

Solve the following system of equations using substitution. 4x + 2y = 12 x = y + 3

Mathematics

2 answers:

BigorU [14]3 years ago

4 0

Answer:

x = 3

y = 0

Step-by-step explanation:

The method of substitution is when one solves an equation for one of the variables, and then substitutes the expression into the other equation. After doing so, one will solve the other equation for the remaining variable and then backsolve for the first variable.

4x + 2y = 12

x = y + 3

The second equation is already sovled for parameter (x), subttiute this into the other equation,

4(y + 3) + 2y = 12

Distribute,

4y + 12 + 2y = 12

Simplify,

6y + 12 = 12

Inverse operations,

6y + 12 = 12

-12

6y = 0

y = 0

Backsolve for (x), substitute the value of (y) into the equation for (x) and solve,

x = y + 3

x = 0 + 3

x = 3

Afina-wow [57]3 years ago

4 0

Answer: look at the picture, sorry I can’t solve x = y + 3 for x.

Step-by-step explanation: Hope this help :D

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2 years ago

The ball park is selling a hamburger combo. At the end of the day, they collected $103.95. If a total of 21 hamburger combos wer

Evgesh-ka [11]

Answer:

Each combo costed $4.95

Step-by-step explanation:

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103.95 ÷ 21 = 4.95 → $4.95

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2 years ago

Please can some explain how to identify angles that on the same segment?

sp2606 [1]

Step-by-step explanation:

Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Picture 1 a° = a° they are the same

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Picture 3 + 4 Let the obtuse angle MOQ = 2x.

Using the circle theorem, the angle at the centre is twice the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

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This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

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8 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

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3 years ago

Does this set of ordered pairs represent a function?

skelet666 [1.2K]

Yes...because every x value corresponds to exactly one y value

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3 years ago

Read 2 more answers