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marshall27 [118]
3 years ago
8

HELP ME! RIGHT NOW!!

Mathematics
2 answers:
leva [86]3 years ago
7 0
Since that angle all together is 180, 100 is 2z-10 and z is 55
Sauron [17]3 years ago
3 0

Step-by-step explanation:

80+(2z-10)=180 {sum of angles in straight line is 180}

  • 80+2z-10=180
  • 70+2z=180
  • 2z=180-70
  • 2z=110
  • z=110/2
  • z=55

now, 2z-10=2×55-10

=110-10

=100

therefore z=55 & 2z-10=100

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Only one question, correct answer gets brainliest
hodyreva [135]

Answer:

16.3420

Step-by-step explanation:

here is what I got

7 0
2 years ago
Read 2 more answers
Helppppp
sasho [114]

Answer:

186.5 + 2x

Step-by-step explanation:

First, radify 25. Luckily it's a perfect square so it will be 5.

Second, divide within the parentheses. You're expression should look like this.

(93-5+x+42/8)2

Divide 42/8. The decimal form would be 5.25, while the fraction should be 5 1/4.

Third, solve within the parentheses from left to right. Right now you're expression should look like this:

(93-5+x+5.25)2

Add all like terms

93-5+5.25=93.25

Fourth, multiply. Right now the expression should look like this:

(93.25 + x) 2

186.5 + 2x

8 0
3 years ago
Katelyn needs to cover her sofa cushions. If each cushion is a 10 in. by 11 in. by 4 in. rectangular prism, and there are 3 cush
Svet_ta [14]

Answer:

1,164 in²

Step-by-step explanation:

the area of 1 sofa cushion =

2× ( 10×11 + 10×4 + 11×4)

= 2 × (110+40+44)

= 2×(194)

= 388 in²

the fabrics she needs to cover 3 sofa cushions =

3 × 388 = 1,164 in²

3 0
3 years ago
What is an equation of the line that passes through the point 3,-1 and has a slope of 2
vekshin1
An equation that passes through the coordinates (3, -1) and has a slope of 2 would be y=2x-7 because since the slope is positive and is 2/1 the slope rises by 2 and runs 1 to right and eventually passes (3, -1) when it starts at -7 on the y-intercept. Answer: y=2x-7

Hope this helps you and would love brainliest! 
8 0
3 years ago
Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u
Tamiku [17]

Answer:

Step-by-step explanation:

15. \frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx}   \\

16.  \frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }

=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2}  \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\

=> The clause is correct

17. Do the same (16)

18. \frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx

19.

\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\

=> The clause is correct

20. Do the same (18)

21. Left = \frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA}  } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}

Right = cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA}   \\

Same with (16) => Left = Right => The clause is correct

22. Do the same (21)

Too long, i'm so lazy :))))

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3 years ago
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