9514 1404 393
Answer:
A: 144 cm
B: 64 cm
C: 36 cm
Step-by-step explanation:
The volume of a cone is given by ...
V = (1/3)πr²h
Solving for h, we get ...
3V/(πr²) = h
Filling in the given values, we get ...
3(192π)/(πr²) = h
576/r² = h
Then the heights of the different cones are ...
A: r = 2, h = 576/4 = 144 . . . cm
B: r = 3, h = 576/9 = 64 . . . cm
C: r = 4, h = 576/16 = 36 . . . cm
Answer:
Probability is 0.831727
Step-by-step explanation:
The probability can be calculated as below
There are multiple scenarios
Scanerio 1
0 occurance & No damage = 1 - 0.2 - 0.03 - 0.001 = 0.769
Scanerio 2
1 occurance & No damage = 0.2 x ( 1 - 0.7 ) = 0.06
Scanerio 3
2 occurance & No damage = 0.03 x ( 1 - 0.7 )^2 = 0.0027
Scanerio 4
3 occurance & No damage = 0.001 x ( 1 - 0.7 )^3 = 0.000027
P(structure will not suffer any damage) = Scanerio 1 + Scanerio 2 + Scanerio 3 + Scanerio 4 = 0.769 + 0.06 + 0.0027 + 0.000027 = 0.831727
You can use this one app it’s called Cymath it’s really helpful with these types of problems,
Solution:
Given that the point P lies 1/3 along the segment RS as shown below:
To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have
Using the section formula expressed as
![[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
In this case,
where
Thus, by substitution, we have
![\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5B%5Cfrac%7B1%282%29%2B2%28-7%29%7D%7B1%2B2%7D%2C%5Cfrac%7B1%284%29%2B2%28-2%29%7D%7B1%2B2%7D%5D%20%5C%5C%20%5CRightarrow%5B%5Cfrac%7B2-14%7D%7B3%7D%2C%5Cfrac%7B4-4%7D%7B3%7D%5D%20%5C%5C%20%3D%5B-4%2C%5Ctext%7B%200%5Crbrack%7D%20%5Cend%7Bgathered%7D)
Hence, the y-coordinate of the point P is
Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
