I think it means grater or less ? Or positive or negative?
Answer:
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
270 miles
Step-by-step explanation:
So is A is going faster than B so A will reach the destination first.
When will A reach it's destination?
Let's find out.
To solve this problem, the following will come in handy:
Speed=distance/time or time*Speed=distance or time=distance/speed .
time=distance/speed
![T_A=\frac{390}{S_A}](https://tex.z-dn.net/?f=T_A%3D%5Cfrac%7B390%7D%7BS_A%7D)
![T_A=\frac{390}{65}](https://tex.z-dn.net/?f=T_A%3D%5Cfrac%7B390%7D%7B65%7D)
![T_A=6](https://tex.z-dn.net/?f=T_A%3D6)
So it will take bus A 6 hours to cover the distance of 390 miles.
How much time would have it taken bus B to reach that same distance?
![T_B=\frac{390}{45}](https://tex.z-dn.net/?f=T_B%3D%5Cfrac%7B390%7D%7B45%7D)
![T_B=8.\overline{6}](https://tex.z-dn.net/?f=T_B%3D8.%5Coverline%7B6%7D)
So it would have taken bus B
hours to cover a distance of 390 miles.
So the time difference is
hours.
It will take
more hours than bus A for bus B to complete a distance of 390 miles.
So bus B traveled
miles (used the time*speed=distance) after bus A got to it's destination.
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
The cash price of the car includes the amount of the loan plus the amount of the down payment
Cash price=the loan of the car+down payment
First find the amount of the loan by using the formula of the present value of an annuity ordinary which is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv the amount of the loan ?
PMT payment per month 355
R interest rate 0.071
K compounded monthly 12
N time 5years
Pv=355×((1−(1+0.071÷12)^(−12
×5))÷(0.071÷12))
=17,885.56
Cash price=17,885.56+2,500
=20,385.56....answer
400 children and 600 adults bought tickets.
Step-by-step explanation:
Given,
Cost of one child ticket = $14
Cost of one adult ticket = $32
Total attendance = 1000
Revenue generated = $24800
Let,
x be the number of children.
y be the number of adults.
According to given statement;
x+y=1000 Eqn 1
14x+32y=24800 Eqn 2
Multiplying Eqn 1 by 14
![14(x+y=1000)\\14x+14y=14000\ \ \ Eqn\ 3](https://tex.z-dn.net/?f=14%28x%2By%3D1000%29%5C%5C14x%2B14y%3D14000%5C%20%5C%20%5C%20Eqn%5C%203)
Subtracting Eqn 3 from Eqn 2
![(14x+32y)-(14x+14y)=24800-14000\\14x+32y-14x-14y=10800\\18y=10800\\](https://tex.z-dn.net/?f=%2814x%2B32y%29-%2814x%2B14y%29%3D24800-14000%5C%5C14x%2B32y-14x-14y%3D10800%5C%5C18y%3D10800%5C%5C)
Dividing both sides by 18
![\frac{18y}{18}=\frac{10800}{18}\\y=600](https://tex.z-dn.net/?f=%5Cfrac%7B18y%7D%7B18%7D%3D%5Cfrac%7B10800%7D%7B18%7D%5C%5Cy%3D600)
Putting y=800 in Eqn 1
![x+600=1000\\x=1000-600\\x=400](https://tex.z-dn.net/?f=x%2B600%3D1000%5C%5Cx%3D1000-600%5C%5Cx%3D400)
400 children and 600 adults bought tickets.
Keywords: linear equations, subtraction
Learn more about subtraction at:
#LearnwithBrainly
That's a lot of points for this question. You don't have to offer that much.
Leading Coefficient: When written in standard form (starting with the variable with the highest power, going to the variable with the next highest power ... all the way down to a number with no variable), the leading coefficient is the number in front of the variable with the highest power.
Let me put this less technically. Find the variable with the highest power. The number in front of that variable is the leading coefficient.
Write this in standard form. 5x^4 -2x + 1
The number in front of the x^4 is the answer.
5 <<<<< answer