( 1 / tan x ) + tan x = 1 / ( sin x cos x )
We will start with the left side:
( 1 / tan x ) + tan x = ( 1 / sinx/cosx ) + ( sin x / cos x ) =
= ( cos x / sin x ) + ( sin x / cos x ) =
= ( cos² x + sin² x ) / ( sin x cos x ) =
= 1 / ( sin x cos x ) , which is same as the right side. The identity is proved.
Answer:
M=0
Step-by-step explanation:
there you go almost sure it is
Lowkey, I'm not sure what this is.
