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klemol [59]
3 years ago
9

What is the domain and range of the function f(x)=2.5^x-6?

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

uh

Step-by-step explanation:

i dont know

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Determine whether the graph represents a proportional relationship.
Ierofanga [76]

Answer:

C- no because the graph is not a straight line

8 0
3 years ago
Use the law of sines to complete an expression that represents the angle measure x
Assoli18 [71]
Answer: 51.9 degrees
Step by step explanation:
Sin(71)/35.6=Sin(x)/21.3
21.3Sin(71)=35.6Sin(x)
21.3Sin(71)/25.6=sin(x)
Sin^-1(21.3Sin(71)/25.6)=x
51.87827502 degrees=x
51.9= angle x
6 0
3 years ago
Important guyz.....
dusya [7]

Answer:

When two functions combine in a way that the output of one function becomes the input of the other, the function is a composite function.

Step-by-step explanation:

In mathematics, the composition of a function is a step-wise application. For example, the function f: A→ B & g: B→ C can be composed to form a function that maps x in A to g(f(x)) in C. All sets are non-empty sets. A composite function is denoted by (g o f) (x) = g (f(x)). The notation g o f is read as “g of f”

3 0
2 years ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
3 years ago
I really need the answers to these cuz they'll make or break my grade
MrMuchimi

Answer:

whats the question? its a little blurry and hard to see

Step-by-step explanation:

8 0
3 years ago
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