Question

For f(x)=4x+1 and g(x)=x^2-5 find (g/f)(x)

Answer 1

$f(x)=4x+1\\\\g(x)=x^2-5\\\\(g/f)(x)=\dfrac{g(x)}{f(x)}=\dfrac{x^2-5}{4x+1}$

Answer 2

Answer:

$(\frac{g}{f})(x)=\frac{x^2-5}{4x+1}$

Step-by-step explanation:

We have been given two function formulas $f(x)=4x+1$ and $g(x)=x^2-5$.

By the definition of composition $(\frac{g}{f})(x)=\frac{g(x)}{f(x)}$.

Upon substituting our given values we will get,

$(\frac{g}{f})(x)=\frac{x^2-5}{4x+1}$

Since we can not simplify our expression further, therefore, $(\frac{g}{f})(x)=\frac{x^2-5}{4x+1}$.