12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
(16)(1) => identity property of multiplication
2(3+7) = 2(3) + 2(7) => distributive property
(2+6) + 3 = 2+ (6+3) => associative property
9+0 = 9 => identity property of addition
8 x 4 = 4 x 8 => commutative property
Answer:
y
=
4
5
x
−
15
Step-by-step explanation:
