Answer:
The probability that a student plays either basketball or soccer is 19% or 0.19.
Step-by-step explanation:
Let A be the event that student play basketball and B be the event that student play soccer.


It is given that 6 students play on both teams.

We have to find the probability that a student plays either basketball or soccer.



Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.
Answer:
(a) 
Step-by-step explanation:
Given


Required
Determine the time in each lap
The unit time in each lap is calculated by dividing the total time by the number of laps; i.e.;

Substitute values for Time and Lap

Answer:
63.5496631543
Step-by-step explanation:
Answer:
0.29
Step-by-step explanation:
We are given that there are 4 couples i.e. 8 people
They decide to play as teams of two and to select the teams randomly
Now we are asked How likely is it that every person will be teamed with someone other than the person he or she came to the party with
For people 1 , there are 6 options for pairing Since he or she cannot pair with his /her own partner
So, Choices For people 1 will be 6 person
So, Probability that person 1 will be teamed with someone other than the person he or she came to the party with = 
So, Probability that every person (=8 person) will be teamed with someone other than the person he or she came to the party with =
Hence Probability that every person will be teamed with someone other than the person he or she came to the party with is 0.29
Hey there, we are given quite a lot of information in this problem. First of all, let's make an equation.
y = x - 22
where y = student's age
where x = instructor's age
this equation is correct because x(instructor) - 22 will yield the student's age (y).
If the instructor were 44 years old, the student would be 22 years old.
y = 44 - 22
y = 22
If the instructor were 66 years old, the student would be 44 years old.
y = 66 - 22
y = 44