Answer:
In a proper volleyball ready position, the knees are bent, the hands are out in front of the player at waist level and just outside the knees, and the player's weight is balanced forward.
Answer:
32 dollars
Step-by-step explanation:
Let's say the original price is x
Create an equation:
Add 5 on both sides
x = 32
The answer is 32 dollars
Hope this helps :)
Have a nice day!
<h2>•5×7^2</h2>
<em>HOPE</em><em> </em><em>ITS</em><em> </em><em>HELPFUL</em><em> </em>^_^
<h2>
•RHONA</h2>
Answer:
Option D.
Step-by-step explanation:
Consider option D. 
Take point (0,0)
On putting this point in inequation 
, we get
which is true . So, solution is region towards the origin i,e region below the line 
including the line itself .
On putting (0,0) in inequation 
, we get 
which is false , so solution is region away from the origin i.e region below line 
including the line itself .
So, common solution to both the inequations is the shaded part in the given figure .
In other words, we can say that the graph shown in the given figure represents system of equations:
Answer: First Option
<em>The points have the same x-coordinate value.</em>
Step-by-step explanation:
By definition, a relation is considered a function if and only if for each input value x there exists <u><em>only one </em></u>output value y.
So, the only way that the line that connects two points in the coordinate plane is not a function, is that these two points have the same coordinate for x.
For example, suppose you have the points (2, 5) and (2, 8) and draw a line that connects these two points.
The line will be parallel to the y axis.
Note that the value of x is the same x = 2. But when x = 2 then y = 5 and y = 8.
There <u><em>are two output</em></u><em> </em>values (y = 8, y = 5) for the same input value x = 2.
In fact all the vertical lines parallel to the y-axis have infinite output values "y" for a single input value x. Therefore, they can not be defined as a function.
<u>Then the correct option is:
</u>
<em>The points have the same x-coordinate value.</em>
