Answer:
(12.1409, 14.0591
Step-by-step explanation:
Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.
Group Group One Group Two
Mean 87.600 74.500
SD 1.000 1.500
SEM 0.316 0.433
N 10 12
The mean of Group One minus Group Two equals 13.100
standard error of difference = 0.556
90% confidence interval of this difference:
t = 23.5520
df = 20
Answer:
8%
Step-by-step explanation:
70.20-65=5.20
5.20/65 x 100 = 8
PERIOD!!!
I can't answer your question without a picture... Sorry.
Answer:
m∠a = 60°
Step-by-step explanation:
Hi there,
Before answering this question, you should know that the sum of all the angles in a triangle will always be 180°. Therefore, we can write this equation to find the value of ∠a :
70° + 50° + m∠a = 180°
Solve for m∠a
120° + m∠a = 180°
m∠a = 60°
Hope this answer helps. Cheers.
The first if a twisted version of a Fibonacci sequence :P
If a1=1.2 and a2=2.3 and a(n)=a(n-1)+a(n-2)
a3=3.5, a4=5.8, a5=9.3
So the first five terms are: 1.2, 2.3, 3.5, 5.8, 9.3
The second is another modified Fibonacci sequence...
If a3=-5 and a4=3 then:
3=-5+a2, a2=8
-5=8+a1, a1=-13
a5=-5+3=-2
a6=-2+3=1
So the first six terms are -13, 8, -5, 3, -2, 1
