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Nina [5.8K]
2 years ago
13

University of North Texas has 3500 less than twice the number of students

Mathematics
1 answer:
DochEvi [55]2 years ago
8 0

Answer:

ok

Step-by-step explanation:

1st step is ask a question.

2nd is get an accurate answer by asking a valid question.

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Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is 2/5?
Gnesinka [82]
Parallel: line p with slope 2/5
Perpendicular: line n with slope -5/2
the other two would be neither.
3 0
3 years ago
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Trevion is training for a marathon. In February, he ran XLVII miles for his training. In January, he was only able to run XXIV m
Sonja [21]

Answer:

c.23

Step-by-step explanation:

easy keep sendin em

3 0
3 years ago
1. Fill in the blanks for the rules for working with exponents:
natima [27]
1.a)add
B) substract
C) multiply
D) one

2) 1002=1.002×10^3

3)2.8×10^-3 < 2.5×10^-2 < 1.2×103 <4×103
5 0
3 years ago
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Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
Help me in both please it’s a test and i need help
nataly862011 [7]

1. -2x + 3y + 5

A. -x + -x + y + y + y + 1 + 1 + 1 + 1 + 1

B. -x + -x + 2y + y + 4 + 1

D. -5x + 3x + 4y - y + 4 + 1

2. -$40 + 100 = $60 - $50 = $10

Cindy currently has $10 left in her bank account.

5 0
3 years ago
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