How many tens are in 20,000 pounds??

You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

6 0

3 years ago

11x + 6y = 6 then graph the equation

maw [93]

Answer:

Step-by-step explanation:

Use the intercept method of graphing a straight line:

Let x = 0. We get y = 1. This is the y-intercept (0, 1).

Let y = 0. We get x = 6/11. This is the x-intercept (6/11, 0).

Plot both points and then draw a straight line through them.

6 0

3 years ago

Mr. Walker asked his students to use the associative property to find an expression that is equivalent to (13 + 15 + 20) + (20 +

pychu [463]

I got it as 4 when calculating all have the same number which is 133

7 0

3 years ago

If yard is 3 feet long how many inches are in a yard

Alla [95]

There are 12 inches in a foot and if a yard is 3 feet then do:
3 x 12 and you get 36in
So there are 36 inches in a yard

7 0

3 years ago

Three friends fill bags with trash at a neighborhood cleanup. Randall's bag weighs

BabaBlast [244]

Answer:

Randall picks up 68 pounds

Seth picks up 40 pounds

Joanna picks up 52 pounds

Step-by-step explanation:

Let us make an equation in x to find it

∵ Randall's bag weighs 3x - 7 pounds

∵ Joanna's bag weighs 2x + 2 pounds

∵ Seth's bag weighs 2x - 10 pounds

∵ Randall's and Joanna's bags weigh 3 times as much as Seth's bag

- That means add Randall's bag and Joanna's bag and equate

the sum by 3 times Seth's bag

∵ Randall's bag + Joanna's bag = 3(Seth's bag)

∴ (3x - 7) + (2x + 2) = 3(2x - 10)

- Simplify the two sides

∴ (3x + 2x) + (-7 + 2) = 3(2x) - 3(10)

∴ 5x + (-5) = 6x - 30

∴ 5x - 5 = 6x - 30

- Add 5 to both sides

∴ 5x = 6x - 25

- Subtract 6x from both sides

∴ -x = -25

- Divide both sides by -1

∴ x = 25

Substitute x by 25 in the weight of each bag

∵ Randall's bag weighs = 3(25) - 7 = 75 - 7

∴ Randall's bag weighs = 68 pounds

∵ Seth's bag weighs = 2(25) - 10 = 50 - 10

∴ Seth's bag weighs = 40 pounds

∵ Joanna's bag weighs = 2(25) + 2 = 50 + 2

∴ Joanna's bag weighs = 52 pounds

7 0

3 years ago

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