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2 years ago

Heyyyyyyyyyyyy plsss helppppppppp

Mathematics

2 answers:

11111nata11111 [884]2 years ago

7 0

Answer:

x = 8

Step-by-step explanation:

Move all terms which do not contain x to the right side and solve.

Iteru [2.4K]2 years ago

7 0

Answer:

x=8

Step-by-step explanation:

- 4x - 8 = -40

+8 +8

- 4x = - 32

4x = 32

x = 8

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Pls help i will give u brianliest

Fynjy0 [20]

Answer:

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

Step-by-step explanation:

We can take any two input-output pairs from the table to find the equation of given function.

Linear function is given by:

$y =mx+b$

Here m is the gradient of the functions which is defined as:

$m = \frac{rise}{run} = \frac{y_2-y_1}{x_2-x_1}$

The input-output pairs are:

(x1,y1) = (-1,-1)

(x2,y2) = (0,-4)

First of all,

$m = \frac{-4-(-1)}{0-(-1)}\\= \frac{-4+1}{1} = -3$

Putting the value of slope in the equation

$y = -3x+b$

Putting (-1,-1) in the equation

$-1 = -3(-1)+b\\-1 = 3+b\\b = -1-3\\b = -4$

The equation will be:

$y = -3x-4$

Hence,

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

7 0

3 years ago

Can someone help me please

fredd [130]

The answer to that is C.

6 0

2 years ago

The low temperatures for one week in Scottsburg, IN are given below. What was the mean daily low temperature for the week? −7.9°

gogolik [260]

Your answer: -0.8

first you would add all of your temperatures together which would give you -5.6

then you would divide -5.6 by 7 because u have 7 numbers

which would give you your answer!

hope this helps, good luck!

7 0

3 years ago

Read 2 more answers

There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?

anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

Where A is the initial amount, in this case, 7800g.
k is a constant that depends on the half-life.
t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) = 7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0

2 years ago

Center city has a population of twenty one thousand seventy people write the populationin standard form

Digiron [165]

It would be 21070

In standard form, 20000+1000+70

5 0

3 years ago

Read 2 more answers