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3 years ago

Please help me I am its in the pic

Mathematics

1 answer:

tiny-mole [99]3 years ago

6 0

Answers:

1. gh = -21

2. g^2 - h = 46

3. g + h^2 = 2

4. g + h = -4

5. h - g = 10

6. g - h = -10

Step-by-step explanation:

1. -7 x 3 = -21

2. -7^2 = - 49

-49 + 3 = -46

3. 3^2 = 9

-7 + 9 = 2

4. -7 + 3 = -4

5. 3 - -7 = 3 + 7 = 10

6. -7 - 3 = -10

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Line m in xy plane contains the points (2,4) and (0,1) which of the following is the equation of M

HACTEHA [7]

Answer:

The equation of line M in slope intercept form is $y=\frac{3}{2}x+1$

The equation of line M in standard form is $3x-2y=-2$

Step-by-step explanation:

step 1

Find the slope of line M

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have the points

(2,4) and (0,1)

substitute

$m=\frac{1-4}{0-2}$

$m=\frac{-3}{-2}$

$m=\frac{3}{2}$

step 2

Find the equation of the line M in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{3}{2}$

$point\ (0,1)$

substitute

$y-1=\frac{3}{2}(x-0)$

$y-1=\frac{3}{2}x$ ----> equation in point slope form

step 3

Find the equation of line M in slope intercept form

$y=mx+b$

Isolate the variable y in the equation of the line in point slope form

$y-1=\frac{3}{2}x$

Adds 1 both sides

$y=\frac{3}{2}x+1$

step 4

Find the equation of the line M in standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=\frac{3}{2}x+1$

Multiply by 2 both sides

$2y=3x+2$

$3x-2y=-2$ ---> equation in standard form

7 0

3 years ago

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

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3 years ago

40% of the students passed both exams. 80% of the students passed the second exam. how many students (in percent) who passed the

navik [9.2K]

50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:

40/80 = 1/2 = 50%.

Find out more on Percentage at:

brainly.com/question/24877689

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7 0

1 year ago

Find the minimum point for the function f(x) = |2x - 1| (0, ½) (½, 0) (0, -½) (-½, 0)

torisob [31]

Minimum point of an absolute value function is when f(x) = 0
0 = <span>|2x - 1|
2x</span> - 1 = 0
2x = 1
x = 1/2

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3 years ago

The line with equation y + 2x = 0 coincides with the terminal side of an angle θ in standard position in Quadrant IV .

Ket [755]

Answer:

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Step-by-step explanation:

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3 years ago