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3 years ago

All of the following are equivalent except _____. 1.25 12.5% 5 over 4 125%

Mathematics

1 answer:

andreev551 [17]3 years ago

3 0

Answer:

brainly deleted my answer but here it is again the answer is B.) 12.5%

Step-by-step explanation:

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The bakers fits 26 rolls on to a pan that measures 1 5/8ft2. How many square feet does the baker use for each roll

mihalych1998 [28]

Answer: 1/16 ft²

Step-by-step explanation:

The baker put 26 rolls into a pan that has an area of 1⁵/₈ ft².

Each roll is therefore taking up a space of:

= Area/ Number of rolls

Convert the fraction to an improper fraction:

1 ⁵/₈ = 13/8

= 13/8 ÷ 26

= 13/8 * 1/26

= 13/208

= 1/16 ft²

6 0

3 years ago

Janet has three times as many dimes as nickels and twice as many quarters as nickels. If she has $3.40 in all, how many nickels,

lord [1]

Let N be no. of nickles. Then N($.05)+3N($.10)+2N($.25)=$3.40.

Or

4 nickels = $0.20
12 dimes = $1.20
8 Quarters = $2.00

Total = $3.40

6 0

3 years ago

Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible

Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

$pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

$or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} }$

By simplifying it we get,

$8$

Now,

again finding the distance between PR,

$pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} }$

or,

$\sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} }$

By simplifying it we get,

$= \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 }$

now, finding the distance of QR,

$qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} }$

or, by simplification we get,

$\sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

now, equating PR and QR,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 }$

we cancelled the root ,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29$

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

$\sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8}$

cancel the roots,

${x}^{2} + {y}^{2} + 6x - 4y + 13 = 8$

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

Hope it helps...

3 0

4 years ago

If point A is translated 4 units left and 6 units down, what are the coordinates of A?

Svet_ta [14]

Answer:C (-2, 1)

Step-by-step explanation:

8 0

3 years ago

Help me please but PLEASE NO LINKSSSSS

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

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3 years ago

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