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MArishka [77]
3 years ago
7

Find the 7th term in the geometric sequence. 0.02, 0.2, 2, 20, ...

Mathematics
1 answer:
vivado [14]3 years ago
7 0

The rule is x10

so 20 is the 4th term of this sequence

200, 2000, 20000,

5th,    6th,    7th,    

The 7th term is 20,000

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at a snack, a milkshake costs $1.19, a cheeseburger costs $3.19, and an order of sweet potato fries costs $2.89. austin is going
ExtremeBDS [4]

9514 1404 393

Answer:

  $50.89

Step-by-step explanation:

The total cost for one meal is ...

  $1.19 +3.19 +2.89 = $7.27

The cost of 7 of these meals will be ...

  7 × $7.27 = $50.89

It will cost Austin $50.89 for the seven meals.

3 0
3 years ago
Joanne buys a rectangle rug with an area of 34/4 square meters the length of the rug was 7/2
Marrrta [24]

Answer:

5/2

Step-by-step explanation:

area formula = l*w=A

in this case l=7/2, and A=35/4

7/2*w=35/4

divide  7/2 with 35/4 to get the value of "w"

35/4*2/7=5/2

hope this helps, if it does plz vote my answer the brainiest, thanks!

4 0
3 years ago
Which solution is shown above?
KATRIN_1 [288]
D is the answer for this one as well
4 0
3 years ago
It is reported that 50% of all computer chips produced are defective. Inspec- tion ensures that only 5% of the chips legally mar
12345 [234]

Answer:

probability of defective  = 0.0545

Probability of a chip to be stolen = 0.0917

Step-by-step explanation:

given data

all computer chips produced are defective = 50%

legally marketed are defective = 5 %

stolen = 1%

solution

we get here probability of defective that is

probability of defective = P ( insepected and defective + stolen and defective)  .........................1

put here value

probability of defective = (1 - 0.01) × 0.05 + 0.01*0.5

probability of defective  = 0.0545

and

So, Probability of a chip to be stolen given defective  =P (stolen and defective) ÷ P(defective)           ......................2

put here value

Probability of a chip to be stolen = 0.01 × 0.5 ÷ 0.0545

Probability of a chip to be stolen = 0.0917

4 0
3 years ago
How to get the greatest common of 45 and 81
erastova [34]
Find the factors and get the ones common to both of them

45=3 times 3 times 5
81=3 times 3 times 3 times 3
so the factors common to both are 3 times 3 which is 9




5 0
3 years ago
Read 2 more answers
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