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ddd [48]
2 years ago
5

(HELP 10 POINTS ) Find (x+3)(x2−2x−8). Write your answer in standard form.

Mathematics
1 answer:
Nina [5.8K]2 years ago
5 0

Answer:

x^{3}+x^{2} -14x-24

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Replacing the maximum value of the data set with a smaller number will also affect the mean. A:always B:sometimes C:never
olga nikolaevna [1]

Answer:

B: sometimes

Step-by-step explanation:

Let's look at two examples.

Example A.

2, 3, 5: mean is 3

Replace 5 with 1. Now you have 1, 2, 3: mean is 2.

In this case, it affected the mean.

Example B.

2, 3, 5: mean is 3

Replace 5 with 4. Now you have 2, 3, 4: mean is 3.

In this case, it did not affect the mean.

As you can see, replacing the maximum value of the data set with a smaller number may or may not change the mean.

Answer: B: sometimes

8 0
2 years ago
The following cube has a volume of 8000 cm3. Find the length of one side of the cube.
Artemon [7]
<span>Vcube = Ledge^3
8000cm^3 = Ledge^3

use the cube root of each side and you have the measure of an edge in cm.

8000^(1/3) = 20
  every edge is 20 cm

20^2 = 400
The area of each face is 400 cm^2. </span>
6 0
2 years ago
X 3) Find the product of 3 x 4 2/3 * O 18 3/4 O 12 6/3 or 14 o 71/2 (0) 14​
ladessa [460]

D. \: 14 \: ✅

Step-by-step explanation:

3 \times 4 \frac{2}{3}  \\  = 3 \times  \frac{14}{3}  \\ =   14

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

5 0
2 years ago
Read 2 more answers
Find the volume of a sphere with a surface area of 576 in.
Kitty [74]

Answer:

Since we have given that

Surface area of sphere = 576 pi cm. sq.

As we know the formula,

Surface area of sphere is given by

So, the volume of a sphere would be

Hence, the required volume is 7241.14 cm³.

Step-by-step explanation:

4 0
3 years ago
HELP PRECALC DO NOT UNDERSTAND WILL GIVE BRAINLIEST
Olegator [25]

Answer:

  the lower right matrix is the third correct choice

Step-by-step explanation:

Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).

Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.

__

We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.

The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...

  \left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]

Already, we see that the second row matches that in the lower right matrix.

The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.

The correct choices here are the two you have selected, and <em>the lower right matrix</em>.

3 0
3 years ago
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