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vredina [299]
2 years ago
14

A motorized scooter normally sells for $560. The scooter was discounted 45% for a sale. After the sale was over, the new price o

f the scooter was 20% higher than the sale price, what was the the new price of the scooter?
Mathematics
1 answer:
beks73 [17]2 years ago
6 0

Answer:

420

Step-by-step explanation:

subtract the percentage which you get 25 percent 560 minus 25 percent is 420

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Find the surface area of the right rectangular shown below hurry plss
laila [671]

Surface area of a cuboid

= [2(length)(width)] + [2(width)(height)] + [2(height)(length)]

= {[2(4)(2.5)] + [2(2.5)(2)] + [2(2)(4)]} units²

= (20 + 10 + 16) units²

= 46 units²

7 0
2 years ago
Read 2 more answers
Type the correct answer in each box. If necessary, use /for the fraction bars
Vikentia [17]

Answer:

The experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

Step-by-step explanation:

The complete question is:

Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).

A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes.

3, 4, 5, 2, 7, 1, 3, 7, 2, 6, 2, 1, 7, 3, 6, 1, 8, 3, 5, 6

The experimental probability of rolling an odd number is _%, which is _% more than the theoretical probability.

Solution:

The possible outcomes of rolling an 8-sided die are:

S = {1, 2, 3, 4, 5, 6, 7, 8}

The odd numbers are:

Odd = {1, 3, 5, 7} = 4 outcomes

The theoretical probability of rolling an odd number is:

P_{T}(\text{Odd})=\farc{4}{8}=\frac{1}{2}=50\%

Now from the given 20 outcomes the odd values are:

Odd = {3, 5, 7, 1, 3, 7, 1, 7, 3, 1, 3, 5} = 12 outcomes

Compute the experimental probability of rolling an odd number as follows:

P_{E}(\text{Odd})=\frac{12}{20}=\frac{3}{5}=60\%

Thus, the experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

6 0
2 years ago
What are the chances your flight will leave on time? Below are a histogram and summary statistics for the percentage of flights
Jet001 [13]

Answer:

80.0456<\bar x<81.1210

Step-by-step explanation:

-Given the mean, \bar y=80.5833 and s=2.77369, the confidence interval can be calculated using the formula:

\bar x\pm z\times \frac{\sigma}{\sqrt{n}}

#We substitute our values in the formula to solve for CI:

=\bar x\pm z\times \frac{\sigma}{\sqrt{n}}\\\\=\bar y\pm z_{0.05}\times \frac{s}{\sqrt{72}}\\\\=80.5833\pm 1.645\times \frac{2.77369}{\sqrt{72}}\\\\=80.5833\pm0.5377\\\\=[80.0456,81.1210]

Hence, the confidence interval lies between 80.0456 and 81.1210

4 0
3 years ago
A race track is made from two straights and two semicircles. The straights are 80m long. The race track has a total perimeter of
Dmitriy789 [7]

Answer:

76.4 m

Step-by-step explanation:

The race track has two straights and two semi circles.

Each straight is 80m

total perimeter for the straights is 80 * 2 = 160m

two semi circles which creates a full circle

perimeter of a full circle = \pi d

NB : (d) is the diameter

therefore we can find the value of the diameter

400 = 160 + \pi d

400- 160 = \pid

240 = \pid

d = 240/\pi

d = 76.394.....

<u>d = 76.4 m</u>

3 0
3 years ago
Which is a graph of f(x) = (6x-2)/(x-3), with any vertical or horizontal asymptotes indicated by the dashed lines?
Margaret [11]

Answer:

to find the vertical asymptote, you have to put the rational function in the simplest form, which means to cancel any common factor between the numerator and denominator. here we don't have anything to cancel. then take the denominator and equal it to 0. x-3=0 ,x=3

to find the horizontal asymptote, in this situation, the degree of the numerator and denominator are the same which is 1. therefore, y=the coefficient of the numerator ÷ the coefficient of the denominator. y=6÷1 ,y=6

7 0
3 years ago
Read 2 more answers
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