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enyata [817]
3 years ago
10

The entire question is un the picture

Mathematics
1 answer:
n200080 [17]3 years ago
7 0
A) 6x -5y = 5
B) 3x + 5y = 4
Adding the equations:
9x = 9
x = 1

A) 6*1 -5y = 5
A) 6 - 5 = 5y
A) 5y = 1
y = 1/5 = .2


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lbvjy [14]

Answer:

4 {x}^{2}  - 2x + x = 5 {x}^{2}  + 2x \\ 4 {x}^{2}  - x = 5 {x}^{2}  + 2x \\ 4 {x}^{2}  - 5 {x}^{2}  = 2x + x \\  - 1 {x}^{2}  = 3x \\  - x = 3 \\ x =  - 3 \\ thank \: you

5 0
3 years ago
Read 2 more answers
Given g(x)= -x-4, solve for x when g(x) =10
dalvyx [7]

Answer:

10 =  - x - 4 \\ 10 + 4 =  -  \times  \\ 14 =  - x \\ x =  - 14

5 0
3 years ago
PLZ HELP 70 POINTS!!!!!
marin [14]

5^(x+7)=(1/625)^(2x-13)


We move all terms to the left:


5^(x+7)-((1/625)^(2x-13))=0



Domain of the equation: 625)^(2x-13))!=0


x∈R



We add all the numbers together, and all the variables


5^(x+7)-((+1/625)^(2x-13))=0


We multiply all the terms by the denominator



(5^(x+7))*625)^(2x+1-13))-((=0


We add all the numbers together, and all the variables


(5^(x+7))*625)^(2x-12))-((=0


We add all the numbers together, and all the variables


(5^(x+7))*625)^(2x=0

not sure if this is right :/


8 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME???
sp2606 [1]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write an equation of the line passing through the point A(2, 0) that is parallel to the line y = 3x−5 .
sammy [17]
Hello,

In order for lines to be parallel to each other, they need to have the same slope. So, let's plug in the points and slope for point-slope form.

The equation for point-slope form is: y-y1 = m (x-x1)

Let's plug in the points into the equation. 
y-5 = m (x-0), and then let's plug in the slope for "m" : y-5 = 3 (x-0).

After plugging the numbers in, the equation is simplified to y-5 = 3 (x-0). Then distribute the 3 to the parenthesis. y-5 = 3x. To get y by itself, you need to add 5 to both sides. After that, the equation parallel to that equation is: y = 3x + 5.

Hope this helps! =)
4 0
3 years ago
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